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3 years ago

What are two different type of mixtures (science)

Chemistry

2 answers:

iren [92.7K]3 years ago

8 0

Answer:

There are two main categories of mixtures: homogeneous mixtures and heterogeneous mixtures.

maria [59]3 years ago

3 0

Answer:

homogenous mixture and heterogeneous mixture

Explanation:

this is the two mixtures

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A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix

Alisiya [41]

Answer:

$M_f=38.8\%$

Explanation:

From the question we are told that:

Pressure $P=747mmHg$

Temperature $T=298K$

Volume $V=11.1$

Heat Produced $Q=780kJ$

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

$n= (747/760) *11.1/ (0.0821*298)$

$n=0.446mol$

Therefore

$x+y=0.446$

$x=0.446-y .....1$

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

$x(889) + y(2220) = 760 ...... 2$

Comparing Equation 1 and 2 and solving simultaneously

$x=0.446-y .....1$

$x(889) + y(2220) = 760 ...... 2$

$x=0.173$

$y=0.273$

Therefore

Mole fraction 0f Methane is mathematically given as

$M_f=\frac{x}{n}*100\%$

$M_f=\frac{1.173}{0.446}*100\%$

$M_f=38.8\%$

7 0

3 years ago

The boiling point of ethanol (C₂H₅OH) is 78.5°C. What is the boiling point of a solution of 6.4 g of vanillin M = 152.14 g/mol)

Gwar [14]

The boiling point of a solution of 6.4 g of vanillin in 50.0g of ethanol is 77.47 degree C.

Change in boiling point of solution

ΔTb = (Kb)(m), where

ΔTb = change in temperature

Kb = elevation constant = 1.22 °C./m

m = molality of the solution

Following the calculation of the moles of vanillin, the molality of vanillin in ethanol will be determined..

Moles of vanillin = 6.4g / 152.12g/mol = 0.042 mol

m of vanillin = 0.042mol / 0.05kg = 0.84m

putting all values on the above equation,

ΔTb = (1.22)(0.84) = 1.0248 °C.

Given;

boiling point of ethanol = 78.5 °C.

So the boiling point of vanillin = 78.5 - 1.0248 = 77.47 °C

Hence, the boiling point of a solution of vanillin is 77.47 °C.

Learn more about the boiling point with the help of the given link:

brainly.com/question/1514229

#SPJ4

6 0

2 years ago

Helppp ! Please :’)

Over [174]

Answer:

$\boxed{\sf \lambda \: = 1.282 \times {10}^{ 3} nm}$

Explanation:

Suppose an electron makes transition from n initial (ni) to n final (nf) then formula for wavelength is given by,

$\frac{1}{ \lambda} = R_H {Z}^{2} \big(\frac{1}{{n_f^2}} - \frac{1}{{n_i^2}} \big)$

Where,

λ is wavelength of photon
Rʜ is rydberg constant, the value of Rʜ is

109690 Cm-¹ in Puri Sharma Pathania standard book of physical chemistry &

109737 Cm-¹ according to Wikipedia

Z is the atomic number of atom, for hydrogen Z =1,

& according to given data, ni = 5, nf = 3

Solution:

Let's solve for wavelength,

Substituting all the given data in above formula,

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \big(\frac{1}{{3^2}} - \frac{1}{{5^2}} \big)$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \big(\frac{1}{{9}} - \frac{1}{{25}} \big)$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \times \frac{25 - 9}{25 \times 9}$

$\frac{1}{ \lambda} = 109690 \times {1}^{2} \times \frac{16}{225}$

$\frac{1}{ \lambda} = 7800.18 \: \: cm ^{ - 1}$

$\lambda = 1.282 \times {10}^{ - 4} cm$

Now we know that, 1 cm = 10000000 nm,

Converting the wavelength from Cm → Nm

$\lambda \: = 1.282 \times {10}^{ - 4} \times {10}^{7}$

$\lambda \: = 1.282 \times {10}^{ - 4 + 7}$

$\sf \lambda \: = 1.282 \times {10}^{ 3} nm$

$\sf \small Thanks \: for \: joining \: brainly \: community!$

4 0

2 years ago

How many cubic cm^3 would be present in a space that is 5.00 in x 4.00 in x 7.00 in?

Sliva [168]

Okay so just add all of them up the fine the x and the y and d the times that by the size of yiurn four head

5 0

3 years ago

What would be the colour of litmus in sodium carbonate? will make brainliest

gregori [183]

Answer:

the color of the litmus paper will turn into blue color because sodium carbonate is basic in nature

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3 years ago