Answer:
e.none of these
Step-by-step explanation:
Computations For CC for Fraction defective
Sample No d p=d/100
1 0 0
2 0 0
3 2 0.02
4 1 0.01
5 0 0
6 1 0.01
7 2 0.02
8 0 0
Total 0.06
3 sigma control limits for p chart are given by:
hence option e is correct
The solutions to the questions are given below
a)
sample(n) word length sample mean
1 5,4,4,2 3.75
2 3,2,3,6 3.5
3 5,6,3,3 4.25
b)R =0.75
c)
- The mean of the sample means will tend to be a better estimate than a single sample mean.
- The closer the range of the sample means is to 0, the more confident they can be in their estimate.
<h3>What is the students are going to use the sample means to estimate the mean word length in the book.?</h3>
The table below shows sample means in the table.
sample(n) word length sample mean
1 5,4,4,2 3.75
2 3,2,3,6 3.5
3 5,6,3,3 4.25
b)
Generally, the equation for is mathematically given as
variation in the sample means
R =maximum -minimum
R=4.25-3.5
R =0.75
c)
In conclusion, In most cases, the mean of many samples will provide a more accurate estimate than the mean of a single sample.
They may have a higher level of confidence in their estimate if the range of the sample means is closer to 0 than it is now.
Read more about probability
brainly.com/question/795909
#SPJ1
Answer:
answer 1962323
Step-by-step explanation:
It's simply 4,2,0,-2..... the pattern is just subtracting two as you go on.
