Question

For a moving object, the force acting on the object where is directly from the objects acceleration. When a force of 21 N Acts on a certain object, the acceleration of the object is 7 m/s^2. If the acceleration of the object becomes 9 m/s^2, what is the force?

Answer 1

Answer:

$F = 27N$

Step-by-step explanation:

Given

Force directly proportional to acceleration

Force = 21N when Acceleraion = 7m/s^2

Required

Determine the force when acceleration = 9m/s^2

The variation between force (F) and acceleration (A) implies that:

$F\ \alpha\ \ A$

Convert to an equation

$F = mA$

Where m is constant.

When F = 21 and A = 7, we have:

$21 = m * 7$

Solve for m

$m = \frac{21}{7}$

$m = 3$

When A = 9

Substitute 9 for A and 3 for m in $F = mA$

$F = 3 * 9$

$F = 27N$