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3 years ago

5

Mrs. Cousins works in a pool store and earns a 9.5% commission on every swimming pool she sells. How much commission would she e

arn for selling a pool that costs $5,600?

1 answer:

stepan [7]3 years ago

6 0

Answer:

$532

Step-by-step explanation:

19/200 * 5600/1

Cross cancellation makes this:

19/1 * 28/1

19 * 28

(19 * 20) + (19 * 8)

380 + 152

$532 in commission

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Can someone please help me??

aivan3 [116]

Answer:

-16 is the answer after evaluating

Step-by-step explanation:

${b }^{2} - 7b - 6 \\ 5 { }^{2} - 7 \times 5 -6 \\ 25 - 35 - 6 \\ 25 - 41 \\ - 16$

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2 years ago

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Bradley estimated the height of a tree at 2.5 meters. Carla estimated that tree's height at 8 feet.

vredina [299]

Answer: 4.1 feet : 4 feet

Step-by-step explanation:

From the question, we are informed that Bradley estimated the height of a tree at 2.5 meters. Carla estimated that tree's height at 8 feet.

The conversion ratio be used to compare Bradley's and Carla's estimates of the tree's height when measured in feet goes thus:

Since 1 feet = 0.305 meters

2.5 meters will be = 2.5/0.305 = 8.2 feet

Therefore the conversion ratio will be:.

= 8.2 : 8

Reducing to lowest term will be

= 4.1 feet : 4 feet.

= 4.1 : 4

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3 years ago

Tyra wants to arrange 32 tiles in equal rows and columns. how many ways could she organized the tiles? list the factors

Novay_Z [31]

I did this in school!!
You can do it 4 times.
I think...

Your welcome!

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3 years ago

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Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions

monitta

I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take $z=y'$ , so that $z'=y''$ and we're left with the ODE linear in $z$ :

$y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2$

Now suppose $y$ has a power series expansion

$y=\displaystyle\sum_{n\ge0}a_nx^n$
$\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}$
$\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}$

Then the ODE can be written as

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0$

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0$

$\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0$

All the coefficients of the series vanish, and setting $x=0$ in the power series forms for $y$ and $y'$ tell us that $y(0)=a_0$ and $y'(0)=a_1$ , so we get the recurrence

$\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}$

We can solve explicitly for $a_n$ quite easily:

$a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}$

and so on. Continuing in this way we end up with

$a_n=\dfrac{a_1}{n!}$

so that the solution to the ODE is

$y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x$

We also require the solution to satisfy $y(0)=a_0$ , which we can do easily by adding and subtracting a constant as needed:

$y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}$

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3 years ago

I need help for this question.

sattari [20]

Answer:

B

Step-by-step explanation:

The figure is a trapezium with area (A) calculated as

A = $\frac{1}{2}$ h (a + b)

where h is the perpendicular height and a, b the parallel bases

Here h = 8, a = 10 and b = 6, thus

A = $\frac{1}{2}$ × 8 × (10 + 6) = 4 × 16 = 64 cm² → B

4 0

2 years ago