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3 years ago

What is the perimeter of the figure

Mathematics

1 answer:

anastassius [24]3 years ago

6 0

Answer:

Option A.

$P=73.4\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

In this problem we have a triangle with a circle inscribed in it

$A.F=A.B\\C.B=C.D\\E.F=E.D$

step 1

Find the length side B.C

$C.B=A.C-A.B$

substitute the given values

$C.B=23-14=9\ units$

step 2

Find the length side C.D

Remember that

$C.D=C.B$

therefore

$C.D=9\ units$

step 3

Find the length side E.D

we know that

$E.D=E.C-C.D$

substitute the given values

$E.D=22.7-9=13.7\ units$

step 4

Find the length side E.F

Remember that

$E.F=E.D$

therefore

$E.F=13.7\ units$

step 5

Find the length side A.F

Remember that

$A.F=A.B$

therefore

$A.F=14\ units$

step 6

Find the perimeter

$P=23+22.7+13.7+14$

$P=73.4\ units$

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8 0

3 years ago

Read 2 more answers

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$