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Neporo4naja [7]
2 years ago
14

I need help to find an equation on a line

Mathematics
2 answers:
joja [24]2 years ago
6 0
The answer is Y: 2x
WINSTONCH [101]2 years ago
5 0

Answer:

y = 2x + 0

Step-by-step explanation:

The y-intercept is 0 and the slope is 2.

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There are 24 people at a party and each person eats 1/8 of a cake. There was not any cake leftover. How many cakes were at the p
sasho [114]

Answer: 3 cakes were at the party

Step-by-step explanation:

Multiply 1/8*24 to find the exact number of cakes that were at the party

Hope this helps :)

5 0
2 years ago
Read 2 more answers
Six bags of Takis costs $13.50. Five bags of Takis costs $10. Which has
viktelen [127]

Answer:

the correct answer is 5 bags

4 0
2 years ago
Read 2 more answers
It is known that 5% of the population over the age of 30 in a city is a university graduate. Among the 100 people chosen randoml
Novosadov [1.4K]

Answer:

A) 1/3200000

B) 19/20

Step-by-step explanation:

Percentage population of graduates = 5

Proportion of graduates from 100 random samples = percentage × number of samples

Proportion of graduates = 0.05 × 100 = 5

Probability of having 5 graduates among the 100 random samples:

P(1 graduate) = possible outcome / total required outcome

P(1 graduate) = (5 / 100) = 1/20

P(5 graduates) = (1/20)^5

P(5 graduates) = 1/3200000

Probability of never being a graduate = (1 - probability of being a graduate)

Probability of never being a graduate = ( 1 - (1/20)) = 19/20

5 0
3 years ago
Solve x2 − 7x + 12 = 0.<br> x = −3, x = −4<br> x = 3, x = 4<br> x = 2, x = 6<br> x = −2, x = −6
UNO [17]

Answer:

x=4, x=3

B is correct.

Step-by-step explanation:

Given: x^2-7x+12=0

Using middle term splitting factor the left side equation.

x^2-4x-3x+12=0

(x-4)(x-3)=0

Equate each factor to 0 and solve for x

x-4=0    or     x-3=0

x=4 and x=3

Hence, The solution of the equation is 4 or 3

6 0
2 years ago
Using a compass and straight edge, construct a tangent line to a circle from a given exterior point. Evidence of your constructi
AleksAgata [21]
In the figure attached, red circle A and red point B are the circle and external point of interest. Note that we must know where the center of circle A is. If we don't know that, there are construction techniques for finding it, but that is beyond the scope of this answer.

Step 1. Set your compass to a radius greater than half the length of segment AB. Here, we have made the radius AD.

Step 2. Draw arcs above and below the center of segment AB centered at A and B using the radius of Step 1. Here the "arc" is shown a a full (green) circle. Only the points where the arcs intersect (E and F) are of interest, so it is not necessary to draw the full circle.

Step 3. Identify the points of interesection (E and F) of the arcs of Step 2, then draw a line segment between them. This segment (EF) is the perpendicular bisector of AB. Mark point G where it intersects segment AB. As with the green circles, it is not necessary to draw the whole line EF, since we are only interested in the location of the midpoint of AB, which is point G.

Step 4. Using G as the center, and GA or GB as the radius, draw semicircle AHB. The point of intersection H is the only part of that (blue) circle of interest, so it is not necessary to draw the whole thing.

Step 5. Finish the consruction by drawing tangent line BH.

6 0
3 years ago
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