Answer:
i think it is no solution
one
one
many
Step-by-step explanation: i dont know for sure if i am right so i wold double check tried my best
Jason's scores : 80 90 95 85 70 and
Jill's score : 70 75 90 100 95.
Mean of Jason's scores = 
Mean of Jill's scores = 
Now, in order to find the mean absolute deviation, need to find the difference of each score from means.
<u>Mean absolute deviation for Jason's scores.</u>
|84-80| = 4
|84-90| = 6
|84-95| = 9
|84-85| = 1
|84-70|= 14

<u>Mean absolute deviation for Jill's scores</u>
|86-70| = 16
|86-75| = 11
|86-90| = 4
|86-100| = 14
|86-95|= 9

Jill got average quiz score 86 and Jason got 84.
Therefore, Jill got better quiz average.
Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.
Therefore, Jason got more consistent grades.
Answer: 5x - 14
Step-by-step explanation: Combine like terms 4x + x - 14 and turn it into 5x - 14
Answer:
15x - 4y =-50 -----(i)
3x - 2y=-16 --------(ii)
Using Substitution
From (i)
15x=4y-50
x=4y-50/15
Substitute x=4y-50/[15] into eqn (ii)
3x - 2y= -16
3[4y-50]/15 - 2y =-16
Multiply through by 15 to clear the fraction
3(4y - 50) - 30y=-240
12y - 150 -30y=-240
12y-30y=-240+150
-18y = -90
y=90/18
y=5.
Substitute into any eqn of choice to get x
3x - 2y=-16
3x - 2(5)=-16
3x - 10=-16
3x=-16+10
3x=-6
x=-6/3
x=-2.
x= -2
y=5