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Vsevolod [243]
3 years ago
15

Find the slope of the line that contains each of the following pairs of points. (3,-5) (0,0)

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0
Slope = y2-y1/x2-x1
slope = 0 - -5/0 - 3
slope = 5/-3
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What is the area and perimeter for 107 cm
belka [17]
it would be 15 in 2
8 0
3 years ago
Solve the system of equations 4x+5y=-1 and -5x-8y=10 by combining the equations.
Flura [38]

The solutions to the given system of equations are x = 6 and y = -5

<h3>Simultaneous linear equations</h3>

From the question, we are to solve the given system of equations

The given system of equation is

4x+5y=-1

-5x-8y=10

Multiply the <u>first equation</u> by 5 and the <u>second equation</u> by 4

5× (4x+5y=-1)

4× (-5x-8y=10)

20x + 25y = -5

-20x - 32y = 40

------------------------

0x + (-7y) = 35

-7y = 35

y = 35/-7

y = -5

Substitute the value of y into the first equation to find x

4x + 5y = -1

4x + 5(-5) = -1

4x -25 = -1

4x = -1 +25

4x = 24

x = 24/4

x = 6

Hence, the solutions to the given system of equations are x = 6 and y = -5

Learn more on Simultaneous linear equation here: brainly.com/question/12647791

#SPJ1

3 0
2 years ago
HELP ME WITH THIS QUESTION PLEASE!!!!!!!!!!!!
NeX [460]

50 maybe

Step-by-step explanation:

because 200 lollipops 4 in each bag

And 150 pencils 3 in each bag

(i dont think this is right)

4 0
3 years ago
Whats the 11th term of 2,6,18,54
Natalija [7]
The 11th term would be 39,366.

The rule for this sequence is 3n (n times 3). Simplying multiplying by 3 until you get to the 11th term (54 * 3 * 3 * 3 * 3 * 3 * 3), would give you this answer.

I hope this helps!!
8 0
3 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5).
Alexeev081 [22]
Zeros are the x values which make the function equal to zero. Set it up as you would for a binomial with a constant multiplier "k" to account for the y-intercept (0, -5) given.

f(x) = k(x-2)(x-3)(x-5)

Use the y-intercept (0,-5) to solve for k.

-5 = k(0-2)(0-3)(0-5)
-5 = -30k
-5/-30 = k
1/6 = k


The cubic polynomial function is then ..

f(x) = (1/6)(x-2)(x-3)(x-5)
 

Linear factors are the linear (line) expressions you can factor out of the polynomial. They are (x-2), (x-3) and (x-5).


5 0
3 years ago
Read 2 more answers
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