Answer:
See below ↓↓↓
Step-by-step explanation:
<u>Probability of getting heads</u>
- Outcome (head) = 1
- Total outcomes = 2
- P (head) = <u>1/2</u>
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<u>Probability of getting an odd number</u>
- Outcome (odd) = {1, 3, 5} = 3
- Total outcomes = 6
- P (odd) = 3/6 = <u>1/2</u>
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The outcomes are equally likely because the probabiity of each outcome is the same.
The fence is 210 ft long.
There is a post every 3.5 ft.
If you divide 210 ft by 3.5 ft, you get the number of spaces between posts.
(210 ft)/(3.5 ft) = 60
The fence starts with a post. Then there is 3.5 ft of fencing. Then there is another post. Then there is another 3.5 ft of fencing followed by a post. In total there are 61 posts.
Here's another way of thinking of why you end up with 60 posts.
For each 3.5 ft of fencing, you place a post at the end of the fencing.
Since there are 60 3.5-ft-long pieces of fencing, there will be 60 posts, one at the end of each piece of fencing. The first thing that is done is to put the initial post before any fencing is put up. The first post plus 60 more posts add up to 61 posts.
Now that you see why there are 61 posts, we can calculate their cost.
61 * $8.50 = $518.50
Answer: The 95% confidence interval is approximately (55.57, 58.43)
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Explanation:
At 95% confidence, the z critical value is about z = 1.960 which you find using a table or a calculator.
The sample size is n = 17
The sample mean is xbar = 57
The population standard deviation is sigma = 3
The lower bound of the confidence interval is
L = xbar - z*sigma/sqrt(n)
L = 57 - 1.960*3/sqrt(17)
L = 55.5738905247863
L = 55.57
The upper bound is
U = xbar + z*sigma/sqrt(n)
U = 57 + 1.960*3/sqrt(17)
U = 58.4261094752137
U = 58.43
Therefore the confidence interval (L, U) turns into (55.57, 58.43) which is approximate.
Answer:
i think c
Step-by-step explanation:
So the lettuce went up by 0.25 or 25c, now, if we take 1.25 to be the 100%, how much is 0.25 in percentage off of it?
