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nikklg [1K]
2 years ago
5

Please explain I need help with all these

Mathematics
1 answer:
sergey [27]2 years ago
3 0
For all of these you're trying to solve for the variable. The variable is usually a number or symbol.

11) -44+n=36
Step one would be to add 44 to both sides of the equation.

N=80

12) -36=p-91
Step one would be to add -91 to both sides of the equation.

P=55

13) X-225=671
Step one you be to add 225 to both sides of the equation. Although it may seem difficult because of the big numbers, it's the same technique.

14) 19=c-(-12)
Step one on this equation will be a little different. Because there are two negative signs (-), they turn into a plus sign. Remember, two negative signs make a positive sign.

19=c+12

Now you just subtract 12 from each side of the equation.

6=C
You might be interested in
Solve for b. Put your answer in simplest radical form. Show Steps plz!<br><br><br> A = 4πbc + πb^2
sladkih [1.3K]

Answer:

b = -2c ± [√(4π²c² + πA)]/π

Step-by-step explanation:

A = 4πbc + πb^2

A = 4πbc + πb²

πb² + 4πbc - A = 0

Using the quadratic formula to solve this quadratic equation.

The quadratic formula for the quadratic equation, pb² + qb + r = 0, is given as

b = [-q ± √(q² - 4pr)] ÷ 2p

Comparing

πb² + 4πbc - A = 0 with pb² + qb + r = 0,

p = π

q = 4πc

r = -A

b = [-q ± √(q² - 4pr)] ÷ 2p

b = {-4πc ± √[(4πc)² - 4(π)(-A)]} ÷ 2π

b = {-4πc ± √[16π²c² + 4πA]} ÷ 2π

b = (-4πc/2π) ± {√[16π²c² + 4πA] ÷ 2π}

b = -2c ± [√(4π²c² + πA)]/π

Hope this Helps!!!

4 0
3 years ago
A square piece of paper 150 millimeters on a side is folded in half along a diagonal. What is the exact length of the diagonal?
s344n2d4d5 [400]

Answer:

Look below.

Step-by-step explanation:

a^{2}+b^{2}  =c^{2} \\150^{2}+150^{2}= c^{2}\\22500+22500=c^{2} \\\sqrt{45000}   = c\\

Use a calculator.

6 0
3 years ago
Use the given information to draw a box-and-whisker plot of the data set
drek231 [11]

Answer:

The box-and-whisker plot of this distribution is presented in the attached image to this solution.

Step-by-step explanation:

A box plot gives a visual representation of the distribution of the data, showing where most values lie and those values that greatly differ from the rest, called outliers.

A box and whiskers plot shows 5 major information about the distribution of data. It shows:

- The maximum variable.

- The minimum variable.

- The Median.

- The first quartile.

- The third quartile.

Further info such as the range and Inter quartile range can then be obtained from this 5-number summary.

The elements of the box plot are described thus;

The bottom side of the box represents the first quartile, and the top side, the third quartile. Therefore, the width of the central box represents the inter-quartile range.

The horizontal line inside the box is the median.

The lines extending from the box reach out to the minimum and the maximum values in the data set, as long as these values are not outliers. The ends of the whiskers are marked by two shorter horizontal lines.

Variables in the dataset, higher than Q3+(1.5×IQR) or lower than Q1-(1.5×IQR) are considered outliers and are usually shown using dots above the top whisker or below the bottom whisker.

The required boxplot for this question is given in the attached image to this solution.

The median for the boxplot isn't provided, but it was assumed to be midway between the first and third quartile.

Hope this Helps!!!

7 0
3 years ago
Which of the binomials below is a factor of this trinomial?
Andrews [41]

Answer:

B is the correct answer accordingly to your question

7 0
2 years ago
Read 2 more answers
Gavin has $7,500 to invest. He is considering two investment options. Option A pays 4% simple interest. Option B pays 3.15% inte
Leviafan [203]

Solution:

Principal =P= $ 7,500

Option A→(Simple interest)

Rate of interest= R=4%

Time(T_{1})=4 years

Time(T_{2})=6 years

Amount= Principal + Interest(Simple or compound interest)

Formula for Simple interest

S.I=\frac{P\times R\times T}{100}

S.I_{1}=\frac{7500 *4*4}{100}=1200\\\\ S.I_{2}=\frac{7500 *4*6}{100}=1800

Total amount after 4 years when interest is simple= 7500 +1200= $ 8700

Total amount after 6 years  when interest is simple= 7500 +1800= $ 9300

Option B

Formula for amount(A) when interest is 3.15% compounded annually.

A=P*(1+\frac{R}{100})^t

A_{4}=7500*(1+\frac{3.15}{100})^4\\\\ A_{4}=7500*(\frac{103.15}{100})^4\\\\ A_{4}=7500*(1.0315)^4\\\\ A_{4}=7500*1.1320\\\\ A_{4}=8490.60

A_{6}=7500*(1+\frac{3.15}{100})^6\\\\ A_{6}=7500*(\frac{103.15}{100})^6\\\\ A_{6}=7500*(1.0315)^6\\\\ A_{6}=7500*1.2045\\\\ A_{6}=9033.9286

Total amount after 4 years when interest is compounded annually=$ 8491 (approx)

Total amount after 6 years  when interest is compounded annually=$ 9034(approx)

4 0
3 years ago
Read 2 more answers
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