All categories

2 years ago

Alex went bowling. He managed to get 3 strikes after 15 attempts. If you were to

Mathematics

1 answer:

algol132 years ago

5 0

Answer:

Theoretical Probability because its what should happen but experimental is what happens

Step-by-step explanation:

You might be interested in

Factsss i be scared as hell to be in front of the classroom but when we at a dance or we go out to party...we be doin all kinds

DanielleElmas [232]

Answer:

that do be true tho

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Pls help!! These two polygons are similar. 4 2 9 o 15

lina2011 [118]

Answer:

z = 3

Step-by-step explanation:

Similar polygons have the ratio of their corresponding sides equal to each other. There:

9/z = 6/2

Cross multiply

z*6 = 9*2

6z = 18

z = 18/6

z = 3

3 0

3 years ago

No links please Lines L and M are parallel find the measure of angle 7

DerKrebs [107]

Link l = m = parallel

6 0

2 years ago

Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.

Alla [95]

Answer with explanation:

The given expression is:

$2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0$

$\cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}$

Option C

8 0

2 years ago

18. What is the least common denominator of the following fractions? 3/10 and 1/4

Len [333]

Answer:

The denominators of 3 /10 and 1 /4 are 10 and 4.

The factors of 10 are 2 × 5 and 2 × 2

Therfore the LCD should have two 2's and one 5.

This means the answer is:

2 × 2 × 5 = 20

I hope this helps :)

7 0

3 years ago