AB + BC + CD = AD <em>segment addition postulate</em>
+ 8 + 7 = AD
+ 15 = AD
AD + 60 = 4AD
60 = 3AD
20 = AD
AB = = = 5
DE = = = 4
CD + DE + EF = CF <em>segment addition postulate</em>
7 + 4 + EF = CF
11 + EF = CF
Answer: 11 + EF
Note: You did not provide any info about EF. If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.
K=4 add seven on both sides 2x-4y=7 add 4y on both sides 2x=7+4y divide 2 on both sides x=7+4y/2 plug that into original equation 2(7+4y/2)-4y-7=0 7 and 4y cancel out 2(2)=0 4=0