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charle [14.2K]
3 years ago
5

Can movement of matter cannot occur without energy transfer

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0
Yes: example-because if u are running u are using energy
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​ g(x)=−20−3x h(x)=( 2 1 ​ ) x ​ Evaluate. (g\circ h) (-2)=(g∘h)(−2)=left parenthesis, g, circle, h, right parenthesis, left par
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ion

Step-by-step explanation:

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Sketch over the interval [0, 2π] the graph of: y = sin(x + π)<br>​
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solve the inequality /2x-1/≥3

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2 years ago
TIMOROW DUE HELP NOW
Svetlanka [38]

The required percentage error when estimating the height of the building is 3.84%.

<h3>How to calculate the percent error?</h3>

Suppose the actual value and the estimated values after the measurement are obtained. Then we have:

Error = Actual value - Estimated value

Given that,

An estimate of the height, H meters, of a tall building can be found using the formula :

H = 3f + 15

where the building is f floors high.

f = 85

The real height of the building is 260 m.

H = 3f + 15

Put f = 85 in the above formula

H = 3(85) + 15

H = 270 m

Error,

E = \dfrac{270 - 260 }{260} \times 100\\\\E = 3.84 %

So, the required percentage error is 3.84%.

Learn more about percentage error;

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3 0
2 years ago
Find an equation of the line that passes through the point (-6,7) and is perpendicular to the line 12x-18y-72=0
madreJ [45]

Answer:

y=-1.5x-2

Step-by-step explanation:

18y=12x-72

3y=2x-12

y=2/3x-4

Slope=-1.5

7=-6(-1.5)+b

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4 0
3 years ago
4x-3y=2<br> 3x=5y=16<br> solve using substitution method
vodomira [7]

\left\{\begin{array}{ccc}4x-3y=2&|\text{add 3y to both sides}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}4x=3y+2&|\text{divide both sides by 4}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}x=0.75y+0.5&(*)\\3x+5y=16\end{array}\right\\\\\text{substitute}\ (*)\ \text{to the second equation}\\\\3(0.75y+0.5)+5y=16\qquad\text{use distributive property}\\\\(3)(0.75x)+(3)(0.5)+5y=16\\\\2.25y+1.5+5y=16\qquad\text{subtract 1.5 from both sides}\\\\7.25y=14.5\qquad\text{divide both sides by 7.25}

\boxed{y=2}\\\\\text{substitute the value of y to}\ (*):\\\\x=0.75(2)+0.5\\\\x=1.5+0.5\\\\\boxed{x=2}\\\\Answer:\ x=2\ and\ y=2\to(2,\ 2)

7 0
3 years ago
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