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REY [17]
2 years ago
12

A number of recent, high-profile foodborne illness outbreaks have increased americans' awareness of the safety of our food suppl

y. what is the primary cause of foodborne illness in north america?
Biology
1 answer:
irga5000 [103]2 years ago
3 0
The primary cause of foodborne illness in north america is due to ingested bacteria.
The major pathogenic bacterial species are: Salmonella, E.coli, Campylobacter, and Staphylococci
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A medical student makes a transverse cut of a cadaver's leg. The two resulting sections could be referred to as the
Gelneren [198K]
A transverse section cut is a cross section took by slicing, really or through imaging techniques, the body or any part of the body structure, in a horizontal plane, a plane that crosses the longitudinal axis at a right angle. In other words, it divides the body into superior and inferior parts which is also known as the top and bottom parts.
8 0
3 years ago
strong winds and heavy precipitation are common along ......... front a .warm b.high pressure C. occluded d...sattionary
gulaghasi [49]
B. stationary front it has high winds and leaves precipitation, warm front doesn't really have the strong winds.
7 0
2 years ago
The graph below shows population data for two species.
pshichka [43]

Answer:

never give up its an order if you do then so dose life

Explanation:

never give up

3 0
2 years ago
What is an acid?<br> What is the ph level of an acid?
Stels [109]

Answer:

• An acid is an electrolyte that hydrolyses in water to release hydrogen ions.

{ \rm{HA _{(aq)} \:  \:  {}^{ \dashrightarrow} _{ \dashleftarrow} \:  \:  H {}^{ + } _{(aq)} +A {}^{ - }  _{(aq)}}} \\

• pH level of an acid;

  1. Strong acid → 0 - 3.8
  2. Weak Acid → 4.0 - 6.7
7 0
2 years ago
Jason has five equally massed lead fishing weights, each weighing 250 grams. What is the total mass of the five lead fishing wei
algol [13]

Answer:

1250 g=1.25 Kg

Explanation:

We are given that Jason has five fishes of equally massed lead fish weights.

Weigh of each fish =250 grams

We have to find the value of total mass of the five lead fishing weights

Total number of fishes=5

In order to find the total mass we will use unitary method

Total mass is obtained by multiplying the total number of fishes with weight of one fish

Total mass=5\times 250

Total mass of five fishes=1250 g

1 kg =1000g

Then 1250 g=\frac{1250}{1000}=1.25 Kg

Hence, total mass of five lead fishing weights=1250 g=1.25 Kg

3 0
2 years ago
Read 2 more answers
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