<span>20, 19, 13, 23, 16, 15, 17, 17, 15, 15, 22, 19
</span>To find the Median, place the numbers in value order<span> and find the </span>middle<span>.
</span>
13, 15, 15, 15, 16, 17, 17, 19, 19, 20, 22, 23
There are 12 numbers and so we don't have just one middle number, we have a pair of middle numbers:
13, 15, 15, 15, 16,
(17, 17), 19, 19, 20, 22, 23
<span>To find the value halfway between them, add them together and divide by 2:
</span>
17 + 17 = 34
34 ÷ 2 = 17
So the median is A) 17.
Answer:
v > -25/p
r = -5 +7/3w
Step-by-step explanation:
-vp + 40 < 65
Subtract 40 from each side
-vp + 40 -40< 65-40
-vp < 25
Divide by -p. Remember to flip the inequality
-vp/-p > 25/-p
v > -25/p
7w - 3r =15
Subtract 7w from each side
7w -7w- 3r =15-7w
-3r = 15-7w
Divide by -3
-3r/-3 (15-7w)/-3
r = -5 +7/3w
Tomas = t
Grandfather = 10t
10t=100
<u>10t</u> = <u>100
</u>10 10
<u>
</u>t=10
<u>
</u>Tomas is 10 years old.<u>
</u>
The question is asking us to determine the number of rows in which Sam can arrange his 12 black and white and 18 color photos. Sam wants to put them in the equal rows so that each row has either black and white photos only or color photos only. We have to find the GCF ( the Greatest Common Factor ) of 18 and 12. GCF ( 18, 12 ) = 6. So there should be 6 photos in each row if they have to be equal ( the equal number of photos in every row ). 18 = 6 * 3 and 12 = 6 * 2. Therefore the number of the rows is : 3 + 2 = 5. Answer: Sam can arrange his photos in 5 rows<span>. </span>
Step One
======
Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
