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3 years ago

What is the median of the data?

1 answer:

8 0

<span>20, 19, 13, 23, 16, 15, 17, 17, 15, 15, 22, 19

</span>To find the Median, place the numbers in value order<span> and find the </span>middle<span>.
</span>
13, 15, 15, 15, 16, 17, 17, 19, 19, 20, 22, 23

There are 12 numbers and so we don't have just one middle number, we have a pair of middle numbers:

13, 15, 15, 15, 16, (17, 17), 19, 19, 20, 22, 23

<span>To find the value halfway between them, add them together and divide by 2:
</span>
17 + 17 = 34
34 ÷ 2 = 17

So the median is A) 17.

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Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

3 years ago

The maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. A truck measures 162 inches in height.

Bumek [7]

<h2>Answer:</h2>

<em><u>The truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>

<h2>Step-by-step explanation:</h2>

In the question,

The maximum height of the vehicle which is capable of passing under the bridge is 12 feet and 5 inches.

So,

Now we know that,

1 feet = 12 inches

So,

12 feet = 12 x 12 = 144 inches

So,

Total height of the vehicle which is permissible to pass under the bridge is,

12 feet 5 inches = 144 + 5 = 149 inches

Also,

Height of the truck = 162 inches

Therefore, we can see that the permissible height is smaller than the height of the vehicle.

Height of vehicle which is more than permissible height is by,

162 - 149 = 13 inches

<em><u>Therefore, the truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>

7 0

3 years ago

In AIJK, the measure of K=90°, IJ = 8.6 feet, and KI = 4.5 feet. Find

azamat

Answer:

58.4

Step-by-step explanation:

delta math give up

3 0

3 years ago

d(t)=750t/(t+12) where t is the age in years and d is the dosage. what is an expression for the rate of change of a child's dosa

Maksim231197 [3]

This just wants the derivative which you can solve for.
You can do this using a negative expononet or using ...the rational rule forget its name*.... you shoudl get 9000/(t+12)^2

*Quotient rule

3 0

3 years ago

15 1/4 - ? = 12 3/4 plsss help me

wariber [46]

1 and 1/2 is the right one

8 0

2 years ago

Read 2 more answers