Can someone help me please

Explain what the solution to a system of equations is:

WINSTONCH [101]

A solution to a system of equations is a set of values for the variable that satisfy all the equations simultaneously. In order to solve a system of equations, one must find all the sets of values of the variables that constitutes solutions of the system.

3 0

3 years ago

Whats the answer to (−4a2bc4)(−9ab7c3)?

avanturin [10]

Can be rearranged as 4×2×a×b×c×4×9×a×b×7×c×3 negative and negative get cancelled off the seperate numerals from unknown values the we get 6048(abc) squared

8 0

3 years ago

what are the values of a, b, and c in the quadratic equation 0 = x2 – 3x – 2? - a = , b = 3, c = 2 - a = , b = –3, c = –2 - a =

Olegator [25]

$x^2-3x-2=0\\\\\boxed{a=1;\ b=-3;\ c=-2}$

7 0

3 years ago

Read 2 more answers

Find n for which the nth iteration by the Bisection Method guarantees to approximate the root of f(x) = 2x^2 − 3x − 2 on [−2, 1]

Lady_Fox [76]

Answer:

n = 29 iterations would be enough to obtain a root of $f(x)=2x^2-3x-2$ that is at most $10^{-8}$ away from the correct solution.

Step-by-step explanation:

You can use this formula which relates the number of iterations, n, required by the bisection method to converge to within an absolute error tolerance of ε starting from the initial interval (a, b).

$n\geq \frac{log(\frac{b-a}{\epsilon} )}{log(2)}$

We know

a = -2, b = 1 and ε = $10^{-8}$ so

$n\geq \frac{log(\frac{1+2}{10^{-8}} )}{log(2)}\\n \geq 29$

Thus, n = 29 iterations would be enough to obtain a root of $f(x)=2x^2-3x-2$ that is at most $10^{-8}$ away from the correct solution.

You can prove this result by doing the computation as follows:

From the information given we know:

$f(x)=2x^2-3x-2$
$\epsilon = 10^{-8}$

This is the algorithm for the Bisection method:

Find two numbers a and b at which f has different signs.
Define $c=\frac{a+b}{2}$
If $b-c\leq \epsilon$ then accept c as the root and stop
If $f(a)f(c)\leq 0$ then set c as the new b. Otherwise, set c as the new a. Return to step 1.