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4 years ago

Which equation does the graph of the systems of equations solve?

Mathematics

1 answer:

12345 [234]4 years ago

8 0

Look at the intersecting point on the graph and see the ordered pair then wright it down

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HELP QUICK!!

Naya [18.7K]

Answer:

Well, it depends on their heights . If both figures have same height, then the one with greater surface area will have greater volume.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help me with a maths question below

kap26 [50]

The second one orate 3rd one

4 0

3 years ago

Relationship B has a greater rate than Relationship A. This graph represents Relationship A.Which equations could represent Rela

d1i1m1o1n [39]

Answer:

y = 3x

y = 2.2x

y=1/2x

Step-by-step explanation:

i did the test thank me later

5 0

3 years ago

Frank had $65. He spent $2 per day for 7 days. Then he was given $9 to divide equally between himself and his 2 brothers. The fo

natulia [17]

Step-by-step explanation:

65 - 2 × 7 + 9 ÷ 3

65 - 14 + 3

51 + 3 = 54

Option A is the correct answer

6 0

3 years ago

suppose that you have 3000$ to invest. which investment yields the greater return over a 10 year period: 8.04% compounded daily

Ksenya-84 [330]

Answer: Option A: 8.04% compounded daily

<u>Step-by-step explanation:</u>

$A = P\bigg(1+\dfrac{r}{n}\bigg)^{nt}\qquad where\\\\\bullet A = \text{accrued amount (principal plus interest earned)}\\\bullet P = \text{principal (amount invested)}\\\bullet r = \text{rate (in decimal form)}\\\bullet n=\text{number of times compounded in one year}\\\bullet t=\text{time (number of years)}\\\\\\Option\ A:\\A = \text{unknown}\\P=3000\\r=8.04\%\rightarrow 0.0804\\n=\text{daily}\rightarrow 365\\t=10\\\\A=3000\bigg(1+\dfrac{0.0804}{365}\bigg)^{365\times 10}\\\\.\ =\$ 6,702.79$

$Option\ B:\\A = \text{unknown}\\P=3000\\r=8.1\%\rightarrow 0.081\\n=\text{quarterly}\rightarrow 4\\t=10\\\\A=3000\bigg(1+\dfrac{0.081}{4}\bigg)^{4\times 10}\\\\.\ =\$ 6,689.37$

Option A results in the greater amount of money.

7 0

4 years ago