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drek231 [11]
3 years ago
9

Which equation is quadratic in form?

Mathematics
1 answer:
34kurt3 years ago
6 0
Option A is correct.

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Elizabeth brought a box of donuts to share. There are​ two-dozen (24) donuts in the​ box, all identical in​ size, shape, and col
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1st lemon = 6/24
now there's one less donut in the box
2nd custard = 16/23

= (6/24)*(16/23)
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4 years ago
1-8(10x-3) distribute please.
Lera25 [3.4K]

Answer:

-70x + 21

Step-by-step explanation:

1-8 = -7.

-7(10x-3)

Distribute, you get -70x + 21.

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What does the notation f(2) mean?
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The expression "f(x)" means "plug a value for x into a formula f "; the expression does not mean "multiply f and x"! Don't embarrass yourself by pronouncing or thinking of "f(x)" as being "f times x". In notation, the "x" in "f(x)" is called "the argument of the function", or just "the argument".
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!!!PLEASE HELP I'LL GIVE BRAINLIEST AND 30 POINTS!!!
zepelin [54]

If two events are independent, then P(A and B) = P(A) x P(B).

In your situation, you need to solve 0.185 = 0.25 x P(B).

Can you take it from there?

8 0
3 years ago
Consider parallelogram VWXY below.
olchik [2.2K]

note:Parallelogram WXYZ not VWXY & I will answer the questions in the image b'cos I don't get your question.

Answers:

a.(i.)Slope of line YZ = 4/5

(ii.)Line adjacent line YZ is line YX,slope of YX =5/4

b.(i.)Length of line YZ =√41 units

 (ii.)Length of line YX =√41 units

c.WXYZ is a rhombus.

Step-by-step explanation:

a.Slope=gradient(m)=(y₂-y₁)/(x₂-x₁)

(i.)m of line YZ=(y₂-y₁)/(x₂-x₁) where Y(-6,-1) & Z(-1,3)

(I believe you know what the y₂,y₁,x₂ & x₁ stand for.)

So m=(y₂-y₁)/(x₂-x₁),=(3-(-1))/(-1-(-6) =(4)/(5)=4/5

∴m of line YZ is 4/5

(ii.)m of line YX=(y₂-y₁)/(x₂-x₁) where Y(-6,-1) & X(-2,4)

So m=(y₂-y₁)/(x₂-x₁),=(4-(-1))/(-2-(-6) =(5)/(4)=5/4=1.25

∴m of line YX is 5/4

b.(i.)To find the length of line YZ,we have to express it as column vector YZ.

Vector YZ=OZ-OY,Z-Y=(-1,3)-(-6,-1)=(5,4)

Length=√x² plus y²=√5² plus 4²=√25 plus 16=√41 units

∴The length of line YZ is √41 units.

(ii.)To find the length of line YX,we have to express it as column vector YZ.

Vector YX=OX-OY,X-Y=(-2,4)-(-6,-1)=(4,5)

Length=√x² plus y²=√4² plus 5²=√16 plus 25=√41 units

∴The length of line YX is √41 units.

c.WXYZ is a rhombus.

5 0
2 years ago
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