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Gelneren [198K]
3 years ago
13

Find f(g(-2)) if f(x)=-3x/7x-6 and g(x)=8/x

Mathematics
1 answer:
shutvik [7]3 years ago
4 0
<span>g(x)=8/x
</span><span>g(-2)=8/-2 = -4

</span>f(g(-2)) = <span>-3(-4) / [7(-4) -6] = 12 / -34 = -6/17</span>
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Tickets to a hockey game cost $35 each. What is the total cost for 5 tickets?
nordsb [41]

The answer would be $175

Multiply the most by the number of tickets

5 0
2 years ago
Read 2 more answers
Helpppppppppp!!! :( math up ):
HACTEHA [7]

Answer:

A 4/5 × 10 1/2 =8.4

B 2 1/2 × 16/5 =8

C 3 2/3 × 2 1/2 = 330/36 = 9.1666

D 20/3 × 9/10 =6

C IS THE GREATEST because 9.166 is greater than 8.4, 8 and 6

7 0
3 years ago
List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
3 years ago
Which expressions are polynomials?
Katarina [22]
I-1 is the polynomials because I is the linear term and 1 is the constant
4 0
2 years ago
FIND THE ∛ OF 188<br><br> (USE √
s2008m [1.1K]

9514 1404 393

Answer:

 ∛188 ≈ 5.72865

Step-by-step explanation:

Any scientific or graphing calculator or spreadsheet can tell you the cube root of 188.

  ∛188 ≈ 5.72865431598...

__

You know that 5³ = 125 and 6³ = 216, so the root will lie between 5 and 6, closer to 6. As a first approximation, you can figure it is about ...

  x = ∛188 ≈ 5 + (188-5³)/(6³ -5³) = 5 + 63/89 ≈ 5.71

You can figure this much using a 4-function calculator.

A closer approximation (x') can be had using the iteration formula ...

  x' = (2x³ +188)/(3x²)

For x = 5.71, the value of x' is ...

  x' ≈ (2×5.71³ +188)/(3×5.71²) ≈ 560.3388/97.8123 ≈ 5.7287

This value is correct when the root is rounded to 4 decimal places. Another execution of the iteration formula using this value will give the root accurate to 9 decimal places.

4 0
2 years ago
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