In the figure below, ∠APE and ∠EPD are congruent.

Drag each tile to the correct box. not all tiles will be used.

lana66690 [7]

Answer:

$y=\frac{13}{6}x$ $y= \frac{11}{5}x$ $y = \frac{21}{9}x$ $y = \frac{19}{8}x$

Step-by-step explanation:

Given

The attached graph

Required

Equations with higher unit rate

First, calculate the unit rate of the graph

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where:

$(x_1.y_1) = (0,0)$

$(x_2.y_2) = (7,15)$

So:

$m = \frac{15 - 0}{7 - 0}$

$m = \frac{15}{7}$

$m = 2.143$

For the given options.

The unit rate is the coefficient of x

So: $y = \frac{19}{8}x$

Going by the above definition of unit rate.

$m = \frac{19}{8}$

$m = 2.375$

$y = \frac{27}{13}x$

$m = \frac{27}{13}$

$m = 2.077$

$y = \frac{21}{9}x$

$m = \frac{21}{9}$

$m = 2.333$

$y= \frac{11}{5}x$

$m= \frac{11}{5}$

$m= 2.20$

$y = \frac{15}{7}x$

$m = \frac{15}{7}$

$m = 2.143$

$y = \frac{31}{15}x$

$m = \frac{31}{15}$

$y = 2.067$

$y=\frac{13}{6}x$

$m=\frac{13}{6}$

$m=2.167$

The unit rates grater than the graph's from small to large are:

$y=\frac{13}{6}x$ $y= \frac{11}{5}x$ $y = \frac{21}{9}x$ $y = \frac{19}{8}x$

$m=\frac{13}{6}$ $m= \frac{11}{5}$ $m = \frac{21}{9}$ $m = \frac{19}{8}$

4 0

3 years ago

Read 2 more answers

Eight kids can go to the waterpark for $60 how many students go for $195 explain how you know

cupoosta [38]

So $60/8= $7.5 which means each ticket is $7.5
$195/$7.5= 26
That means that 26 students can buy tickets with $195

6 0

3 years ago

For a beverage, Lisa mixes cups of lemonade to cups of iced tea in a ratio of 1:4. Which of the following best describes the amo

dybincka [34]

There is one cup of lemonade to four cups of iced tea.

3 0

3 years ago

A sample of 100 people is classified by gender (male/female) and by whether they are registered voters. The sample consists of 8

uysha [10]

Answer:

12

Step-by-step explanation:

Given :

Male Female Total

Registered 60

Non registered 40

Total 20 80

Solution :

N= 100

Formula of expected frequency = $E_{ij}=\frac{T_i \times T_j}{N}$

$E_{ij}$ = expected frequency for the ith row/jth columm.

$T_i$ = total in the ith row

$T_j$ = total in the jth column

N = table grand total.

So, using formula $E_{11}=\frac{T_1 \times T_1}{100}$

$E_{11}=\frac{60 \times 20}{100}$

$E_{11}=12$

$E_{12}=\frac{T_1 \times T_2}{100}$

$E_{12}=\frac{60 \times 80}{100}$

$E_{12}=48$

$E_{21}=\frac{T_2 \times T_1}{100}$

$E_{21}=\frac{40 \times 20}{100}$

$E_{21}=8$

$E_{22}=\frac{T_2 \times T_2}{100}$

$E_{22]=\frac{80 \times 40}{100}$

$E_{22}=32$

Expected frequency table

Male Female Total

Registered 12 48 60

Non registered 8 32 40

Total 20 80

So, the expected frequency for males who are registered voters are $E_{11}=12$

5 0

3 years ago

What is m∠HLK? thanks

Katen [24]

The answer is 80°.

If there is a line segment in a triangle which cuts two sides in half or if there is a line segment between two midpoints of a triangle's sides, that line segment must be parallel to the remaining side.

In this case, point L is the midpoint of FH, and point K is the midpoint of HG. So, LK is parallel to FG.

When a line cuts two parallel lines, there are angle pairs which are equal. In the problem above, the line segment FH cuts KL and GF.

The angles KLH and GFH are what we called "Corresponding Angles" and they are equal.

So if HFG is 80°, HLK must be equal to 80°

3 0

3 years ago