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Elza [17]
3 years ago
10

In the figure below, ∠APE and ∠EPD are congruent.

Mathematics
1 answer:
Lady_Fox [76]3 years ago
3 0

Answer:

P = 54 so

arc AC = 150

Step-by-step explanation:

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Converse of the Pythagorean theorem
jonny [76]
I only know how to do # 7.

7. 4.5^2 + 6^2 = 7.5^2
20.25 + 36 = 56.25
56.25 = 56.25

yes, the card is a right triangle because A and B added together equals the same as C
7 0
3 years ago
karen has two dogs the larger one weighs 1.4 pounds more then the smaller dog. The combined weight of the two dogs is 12.6 pound
ivanzaharov [21]

Answer:w=5.6

Step-by-step explanation:

there u go

3 0
3 years ago
− 4 /5 + 40/75 +100%
Reika [66]

Answer:

0.266666666

Step-by-step explanation:

7 0
3 years ago
Help me please I dont understand
Vaselesa [24]

Answer:

42°

Step-by-step explanation:

This is right triangle and sum of 2 angles is 90°:

y+48°=90°

so y= 90°- 48°= 42°

4 0
3 years ago
Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0
3 years ago
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