399.6 square meters
7•8/2=28
28•3=84
8•6.9/2=27.6
(12•8)•3=288
84+27.6+288=399.6
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Add sides 6


Divide sides by 2


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The correct answer is (( B )) .
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I believe the the correct answer would be yes. Two lines can be drawn from a point that is not collinear with a certain line that will meet the line at a right angle or 90 degree angle and at an angle of 45 degrees. We can freely draw any line that would pass through a given point and would cross a given line at any direction giving us different angles and this would include a 90 and 45 degree angle.
Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>
The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
__
<h3>(b)</h3>
The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
__
<h3>(c)</h3>
The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q
the quickest way to do this would be to multiply 1,375 by 3 and then add 2.
1,375 * 3 = 4,125 + 2 = 4,127
correct!