Ask question

Ask question

All categories

4 years ago

5

What should be done to both sides of the equation in order to solve w - 9 1/2 = 15? Add 15. Subtract 15. Add 9 1/2. Subtract 9 1

/2.

2 answers:

krek1111 [17]4 years ago

8 0

You want to undo the (-9 1/2), so you will add 9 1/2 to each side

sweet-ann [11.9K]4 years ago

7 0

The answer to this is

D.) Subtract 9 1/2 from 9 1/2 and 15

Hope This Helps!
:D

You might be interested in

The sum of two numbers is 25. Their difference is 9. What are the two numbers?

Lynna [10]

Using x and y as the numbers

x+y=25 -------#1
x-y=9 -------#2

Using addition of #1 and #2
x+y+x-y= 25+9
2x+0y=34
2x=34
x=17

Using the value of x and plugging said value into #1 or #2, we can find y
x=17

x+y=25
17+y=25
y=8

OR

x-y=9
17-y=9
-y=-8
y=8

The numbers are 8 and 17

5 0

4 years ago

Read 2 more answers

Write an expression that represents the sum of 7and x

Lady_Fox [76]

Answer:

$7 + x$

Step-by-step explanation:

............................

6 0

3 years ago

Read 2 more answers

For questions 3 - 5, answer the questions about the equations.

mrs_skeptik [129]

Answer:

infinite solutions

Step-by-step explanation:

Eliminate parentheses and collect terms:

3x -12 +5 -x = 2x -7

2x -7 = 2x -7

This is true for any value of x. There are an infinite number of solutions.

6 0

3 years ago

9th grade math help me please and thank you sosomuch

Varvara68 [4.7K]

Answer:

The system is consistent; it has one solution ⇒ D

Step-by-step explanation:

A consistent system of equations has at least one solution

The consistent independent system has exactly 1 solution

The consistent dependent system has infinitely many solutions

An inconsistent system has no solution

In the system of equations ax + by = c and dx + ey = f, if

a = d, b = e, and c = f, then the system is consistent dependent and has infinitely many solutions
a = d, b = e, and c ≠ f, then the system is inconsistent and has no solution
a ≠ d, and/or b ≠ e, and/or c ≠ f, then the system is consistent independent and has exactly one solution

In the given system of equations

∵ -2y + 2x = 3 ⇒ (1)

∵ -5y + 5x = 12 ⇒ (2)

→ By comparing equations (1) and (2)

∵ -2 ≠ -5

∵ 2 ≠ 5

∵ 3 ≠ 12

→ By using the 3rd rule above

∴ The system is consistent independent and has exactly one solution

∴ The system is consistent; it has one solution

7 0

3 years ago

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago