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4 years ago

:))) help por favor

Mathematics

1 answer:

miskamm [114]4 years ago

3 0

1 and 5 are equal, 1 and 8 are equal, 5 and 8 are equal
So if 1+5=100 and they're equal divide by 2: 100/2=50. So if 1 and 5 equals 50, then 8 also =50 :)

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Suppose a certain manufacturing company produces connecting rods for 4- and 6-cylinder automobile engines using the same product

gregori [183]

Answer:

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

Step-by-step explanation:

The cost for the four cylinder production line is $C_4 = \$2,100$

The cost for the six cylinder production line is $C_6 = \$3,500$

The manufacturing cost for each four cylinder is $M_4= \$13$

The manufacturing cost for each six cylinder is $M_6= \$16$

The weekly production capacity for 4 cylinder connecting rod is $W_4 = 5,000$

The weekly production capacity for 6 cylinder connecting rod is $W_6 = 8,000$

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

3 0

4 years ago

The cost for a company to produce a part for d days is represented by the function f(d)=275d+12,950 what does the value 12,950 r

Helga [31]

Answer:

B.) The initial cost is $12,950

Step-by-step explanation:

Given that:

$f(d)=275d+12,950$

is the function to represent the cost for a company for the production of a part for $d$ number of days.

To find:

What does the value 12,950 represent in the above cost function.

Solution:

The given function contains two parts:

1. One part is multiple of $d$ and

2. Second part is a constant.

Here, $d$ is the number of days.

As $d$ changes, the value also changes but the constant part remains the same.

Therefore, we can conclude that the initial cost for the company is $12,950.

The answer is:

B.) The initial cost is $12,950

7 0

3 years ago

Read 2 more answers

How many solutions does 6x+3y=18

pogonyaev

Answer:

Infinantly many

Step-by-step explanation:

5 0

4 years ago

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Why do both ways of writing the number as tens and ones describe the same number

Reika [66]

Because they are both even numbers

3 0

3 years ago

in 2000 the average cost for a gallon of gasoline was 1.40 in 2007 the average cost for a gallon of gasoline is 2.60 what is the

victus00 [196]

Umm... if in 2000 it was 1.40 and in 2007 it was 2.60, you subtract the two ie 2.60 -1.40 and you will get 1.2
Then, take 1.2 and divide it by 1.40 and then multiply by 100

hope you got it :))

3 0

3 years ago

Read 2 more answers