All categories

3 years ago

:))) help por favor

Mathematics

1 answer:

miskamm [114]3 years ago

3 0

1 and 5 are equal, 1 and 8 are equal, 5 and 8 are equal
So if 1+5=100 and they're equal divide by 2: 100/2=50. So if 1 and 5 equals 50, then 8 also =50 :)

You might be interested in

A doctor sees 13 male patients and 15 female patients one day. Which statement about the doctor's patients is true?

Veronika [31]

Answer:

Step-by-step explanation:

13+15=28

there are 15 males, it does not matter if its a pick, to do a ratio of two numbers add the two and put the number requested to be compared

3 0

3 years ago

Read 2 more answers

Find the equation of the sphere passing through P(negative 4 comma 7 comma 6 )and Q(8 comma negative 3 comma 5 )with its center

Juli2301 [7.4K]

Answer: The equation of the sphere is:

(x-2)^2 + (y-2)^2 + (z-5/2)^2 = sqrt(245)/2

Step-by-step explanation:

The centre of the sphere is the midpoint of the diameter, which is

1/2

[(-4,7,6) + (8,-3,5)] =(2,2,5/2)

The length of the diameter is

=sqrt |(8,-3,5) - (-4,7,6)|^2

=sqrt (12^2 + (-10)^2 + (-1)^2)

=sqrt (144+100+1)

=sqrt(245)

so the radius of

the sphere is:

1/2(sqrt(245)) = sqrt(245)/2.

The equation of the sphere is:

(x-2)^2 + (y-2)^2 + (z-5/2)^2 = sqrt(245)/2

4 0

3 years ago

Alex invests $2,000 in a company's stock. After a year, the value of Alex's stock has increased to $2,500. What rate of return h

Kay [80]

The rate of interest is 25%

<u>Explanation:</u>

Given:

Principal, P = $2,000

Amount, A = $2500

Time, t = 1 year

Rate of Interest, r = ?

We know:

$Amount = P(1+\frac{r}{100})^t$

On substituting the value we get:

$2500 = 2000 (1 + \frac{r}{100})^1\\ \\\frac{25}{20}= (1+\frac{r}{100})\\$

$\frac{5}{20} = \frac{r}{100}\\ \\r = \frac{100 X 5}{20} \\\\r = 25$

Therefore, the rate of interest is 25%

5 0

3 years ago

Read 2 more answers

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior citizen tickets and 4 child ticke

FrozenT [24]

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?

14S + 4C = 200

14S = 200 - 4C

S = (200 - 4C)/14

7S + 1C = 92

7S = 92 - C

S = (92 - C)/7

(200 - 4C)/14 = (92 - C)/7

7 x (200 - 4C) = 14 x (92 - C)

1400 - 28C = 1288 - 14C

1400 - 1288 = 28C - 14C

112 = 14C

C = 112/14 = 8

the price of one child ticket = $8

8 0

3 years ago

.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and

Leni [432]

Answer:

a) Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

b) $t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

Step-by-step explanation:

Information given

$\bar X=130$ represent the sample mean for the amount spent each shopper

$s=40$ represent the sample standard deviation

$n=80$ sample size

$\mu_o =120$ represent the value to verify

t would represent the statistic

$p_v$ represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

The statistic for this case would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

5 0

3 years ago