I need help, quick, it's Algebra but super easy, thank you.

Mathematics

2 answers:

Masja [62]3 years ago

8 0

16- 2(2w+1) = 8w - 2(8+w)

16-4w-2 = 8w- 16 -2w

+2 +2
18-4w= 8w-14-2w
+4w +4w
18= 12w-14+2w
+14 +14
32= 12w+2w
-2w -2w
32=10w
/10
= 3.2

horsena [70]3 years ago

3 0

16 - 2(2w + 1) = 8w - 2(8+w)
16 - 4w - 2 = 8w - 16 - 2w
- 4w + 14 = 6w - 16
14 = 10w - 16
30 = 10w
/10 /10
3 = w

I think so lol

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Find the inverse of the following function:

tigry1 [53]

First, we are going to find the inverse function of $f(x)$ by replacing $f(x)$ with $y$ , and then, interchanging $x$ and $y$ and solving for $x$ :
$y=-2 \sqrt{3x-1} -5$
$x=-2 \sqrt{3y-1} -5$
$-2 \sqrt{3y-1} =x+5$
$\sqrt{3y-1} = \frac{x+5}{-2}$
$3y-1=( \frac{x+5}{-2} )^{2}$
$3y=( \frac{x+5}{-2} )^{2} +1$
$y= \frac{( \frac{x+5}{-2})^{2}+1 }{3}$

Next we are going to evaluate our inverse function at $x= \frac{1}{3}$ :
$y= \frac{( \frac{ \frac{1}{3}+5 }{-2})^{2}+1 }{3}$
$y= \frac{( \frac{ \frac{16}{3} }{-2})^{2}+1 }{3}$
$y= \frac{(- \frac{8}{3})^{2}+1 }{3}$
$y= \frac{ \frac{64}{9}+1 }{3}$
$y= \frac{ \frac{73}{9} }{3}$
$y= \frac{73}{27}$

We can conclude that the inverse function of $f(x)=-2 \sqrt{3x-1} -5$ when $x= \frac{1}{3}$ is $\frac{73}{27}$

5 0

3 years ago

Please help, thank you

madam [21]

Answer:

$\displaystyle x=\frac{-8\pm\sqrt{(8)^2-4(4)(-221)}}{2(4)}\ \text{; x = 6.5 and x = -8.5}$