1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cluponka [151]
3 years ago
12

%5Csqrt%5B3%5D%7Bb%7D%20%2B%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B1%7D%7B9%7D%20%7D%20%5C%5C%20%5C%5C%20If%20%5C%3A%20a%3Eb%20%5C%3A%20%5C%3A%20%2C%20%5C%3A%20%5C%3A%20Find%20%5C%3A%20%5C%3A%20%28a%2B2b%29%20%5C%3A." id="TexFormula1" title=" \sqrt[3]{ \sqrt[3]{2} - 1} = \sqrt[3]{a} + \sqrt[3]{b} + \sqrt[3]{ \frac{1}{9} } \\ \\ If \: a>b \: \: , \: \: Find \: \: (a+2b) \:." alt=" \sqrt[3]{ \sqrt[3]{2} - 1} = \sqrt[3]{a} + \sqrt[3]{b} + \sqrt[3]{ \frac{1}{9} } \\ \\ If \: a>b \: \: , \: \: Find \: \: (a+2b) \:." align="absmiddle" class="latex-formula">

Mathematics
2 answers:
AleksAgata [21]3 years ago
5 0
Define
c=\sqrt[3]{\sqrt[3]{2}-1}-\sqrt[3]{\frac{1}{9}} \approx 0.157435964092

Then you have the symmetrical equation
c=\sqrt[3]{a}+\sqrt[3]{b}
which can be solved for b to give
b=(c-\sqrt[3]{a})^{3}

Substituting into your expression gives
a+2b=a+2(c-\sqrt[3]{a})^{3}

The requirement that a > b means this is only relevant for
a > (\frac{c}{2})^{3} \approx 0.000487777605001

The attached graphs show the general shape of a+2b and some detail near the origin. "a" is plotted on the x-axis; "b" is plotted on the y-axis.

AVprozaik [17]3 years ago
3 0
Step One
Subtract cube root 1/9 to the left hand side. Or subtract cube root (1/9) from both sides.
\sqrt[3]{ \sqrt[3]{2} -1 } -  \sqrt[3]{ \frac{1}{9} } =  \sqrt[3]{a} +  \sqrt[3]{b}

Step Two. 
There is a minus sign in front of {-}\sqrt[3]{ \frac{1}{9} }
We must get rid of it. Because it is a minus in front of a cube root, we can bring it inside the cube root sign like so, and make it a plus out side the cube root sign
 {+}\sqrt[3]{ \frac{-1}{9} }
 
Step Three
Write the Left side with the minus sign placed in the proper place
\sqrt[3]{ \sqrt[3]{2} -1 } + \sqrt[3]{ \frac{-1}{9} } = \sqrt[3]{a} + \sqrt[3]{b}

Step Four
Equate cube root b with cube root (-1/9)
\sqrt[3]{b} = \sqrt[3]{ \frac{-1}{9} }

Step Five
Equate the cube root of a with what's left over on the left
\sqrt[3]{ \sqrt[3]{2} -1 } =  \sqrt[3]{a}

Step 6. 
I'll just work with b for a moment.
Cube both sides of  cube root (b) = cube root (-1/9)
\sqrt[3]{b} ^{3} =\sqrt[3]{ \frac{-1}{9} }^3}
\text{b =} \frac{-1}{9}
\text{2b =}\frac{-2}{9}

Step seven
the other part is done exactly the same way
a = cuberoot(2) - 1.

What you do from here is up to you. It is not pleasant.
Is this clearer?

a + 2b should come to cuberoot(2) - 1 - 2/9
a + 2b should come to cuberoot(2) - 11/9

I hope a person is marking this. I wonder how many of your class mates got it. 
You might be interested in
A city has 3 new houses for every 9 old houses. If there are 21 new houses in the city, how many old houses are there?
kipiarov [429]
To find your answer you would divide 21 by 3 which would be 7, once you've got 7 you would multiply it by 9 which would give you the amount of old houses that there is which would be 63.
5 0
2 years ago
Two angles are supplementary one angle measure 12 more than the other find the measures
Furkat [3]
We have a + b = 180 and a = 12 + b;
Then, 12 + b + b = 180;
12 + 2b = 180;
2b = 168;
b = 84;
a = 12 + 84;
a = 96;
5 0
3 years ago
Which of the following inequalities is correct?
almond37 [142]

Answer:

A

Step-by-step explanation:

because there variables represent 1 so 1 cant be bigger than one and the other two have real equations

6 0
2 years ago
If the domain of the function f(x) = x - 5 is {1, 3, 4, 6} what is the range? F
Margarita [4]

Answer:

-4, -2, -1, 1

Step-by-step explanation:

If the domain is given we use the equation to determine the range but usually the range would be everything in this equation.

7 0
2 years ago
I need help please!
den301095 [7]

9514 1404 393

Answer:

  f(g(x)) = 2/(x^2 +4x)

Step-by-step explanation:

  (f\circ g)(x)=f(g(x))\\\\(f\circ g)(x)=f(x+2)=\dfrac{2}{(x+2)^2-4}\\\\(f\circ g)(x)=\dfrac{2}{x^2+4x+4-4}\\\\\boxed{(f\circ g)(x)=\dfrac{2}{x^2+4x}}

3 0
2 years ago
Other questions:
  • Is √17 rational irrational an integer a whole number or a natural number.
    15·1 answer
  • Determine which two values the following number is between. A. 12 and 13 B. 13 and 14 C. 15 and 16 D. 14 and 15
    15·1 answer
  • In triangle ABC, m a = 45 m b =65 and a = 15.05. Use the law of sines to find b. Round your answer to the nearest tenth.
    10·2 answers
  • 303 is what percent of 600?explain
    10·2 answers
  • Solve each compound inequality. Graph your solutions.<br> 5 + m &gt; 4 or 7m&lt; -35
    11·1 answer
  • Need this ASAP!! Would help if you could answer as quick as possible x
    9·2 answers
  • You are standing 42 feet away from your house. On the top of the roof is a satellite dish, which is 60 feet
    10·1 answer
  • Eli's bedroom door is 9 feet tall and 3 feet wide. A new door is 2. 00 per square foot. How much would a new bedroom door cost i
    15·1 answer
  • Which choice represents the expression below as a single exponential
    13·1 answer
  • Let f(x)=3x+1 and g(x)=x^2+xAfter simplifying (fg)(x)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!