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3 years ago

How to do a double number line

1 answer:

3 0

Draw two straight parallel lines and label with units and arrow as the end
Draw a tick mark through both lines and label with given ratio.
Start with 0 and 0 on each number line.
Label the units of each number line.

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Jess recently started a business producing cosmetic products made from natural ingredients. She wants to advertise her products

kicyunya [14]

Answer in minutes: 342.86

Answer in hours: 5.7143

6 0

3 years ago

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How would I solve this question

zvonat [6]

Tan(ANGLE) = Opposite Leg / Adjacent Leg

Tan(60) = Y/8

Y = 8 x tan(60)

Y = 8√3

Y = 13.9

4 0

3 years ago

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Solution for dy/dx+xsin 2 y=x^3 cos^2y

vichka [17]

Rearrange the ODE as

$\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y=x^3\cos^2y$
$\sec^2y\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y\sec^2y=x^3$

Take $u=\tan y$ , so that $\dfrac{\mathrm du}{\mathrm dx}=\sec^2y\dfrac{\mathrm dy}{\mathrm dx}$ .

Supposing that $|y|$ , we have $\tan^{-1}u=y$ , from which it follows that

$\sin2y=2\sin y\cos y=2\dfrac u{\sqrt{u^2+1}}\dfrac1{\sqrt{u^2+1}}=\dfrac{2u}{u^2+1}$
$\sec^2y=1+\tan^2y=1+u^2$

So we can write the ODE as

$\dfrac{\mathrm du}{\mathrm dx}+2xu=x^3$

which is linear in $u$ . Multiplying both sides by $e^{x^2}$ , we have

$e^{x^2}\dfrac{\mathrm du}{\mathrm dx}+2xe^{x^2}u=x^3e^{x^2}$
$\dfrac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]=x^3e^{x^2}$

Integrate both sides with respect to $x$ :

$\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx$
$e^{x^2}u=\displaystyle\int x^3e^{x^2}\,\mathrm dx$

Substitute $t=x^2$ , so that $\mathrm dt=2x\,\mathrm dx$ . Then

$\displaystyle\int x^3e^{x^2}\,\mathrm dx=\frac12\int 2xx^2e^{x^2}\,\mathrm dx=\frac12\int te^t\,\mathrm dt$

Integrate the right hand side by parts using

$f=t\implies\mathrm df=\mathrm dt$
$\mathrm dg=e^t\,\mathrm dt\implies g=e^t$
$\displaystyle\frac12\int te^t\,\mathrm dt=\frac12\left(te^t-\int e^t\,\mathrm dt\right)$

You should end up with

$e^{x^2}u=\dfrac12e^{x^2}(x^2-1)+C$
$u=\dfrac{x^2-1}2+Ce^{-x^2}$
$\tan y=\dfrac{x^2-1}2+Ce^{-x^2}$

and provided that we restrict $|y|$ , we can write

$y=\tan^{-1}\left(\dfrac{x^2-1}2+Ce^{-x^2}\right)$

5 0

3 years ago

Michael uses a uniform probability model for an experiment using a deck of 45 cards. There are 15 blue card, 15 red cards, and 1

vampirchik [111]

Answer:

<em>P</em> = 2/3

Step-by-step explanation:

45 cards in all

15 blue

15 red

15 green

To figure out the probability of red and blue together, add red and blue.

15 + 15 = 30

Since the total is 45, this is how many 30 will be out of.

30 out of 45 = 30/45

Simplify 30/45 by dividing each side by 15

30 ÷ 15 = 2

45 ÷ 15 = 3

30/45 = 2/3

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2 years ago

I need help with these two questions please!

Novay_Z [31]

The first one is rectangle

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3 years ago

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