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3 years ago

The greatest factor that two or more numbers have in common is the

Mathematics

1 answer:

trapecia [35]3 years ago

8 0

Answer:

"greatest common factor" (GCF) or "greatest common divisor" (GCD)

Step-by-step explanation:

Apparently, you're looking for the term that has the given definition. It is called the GCF or GCD, the "greatest common factor" or the "greatest common divisor."

_____

The GCF or GCD can be found a couple of ways. One way is to find the prime factors of the numbers involved, then identify the lowest power of each of the unique prime factors that are common to all numbers. The product of those numbers is the GCF.

<u>Example</u>:

GCF(6, 9)

can be found from the prime factors:

6 = 2·3
9 = 3²

The unique factors are 2 and 3. Only the factor 3 is common to both numbers, and its lowest power is 1. Thus ...

GCF(6, 9) = 3¹ = 3

Another way to find the GCD is to use Euclid's Algorithm. At each step of the algorithm, the largest number modulo the smallest number is found. If that is not zero, the largest number is replaced by the result, and the process repeated. If the result is zero, the smallest number is the GCD.

GCD(6, 9) = 9 mod 6 = 3 . . . . . (6 mod 3 = 0, so 3 is the GCD)

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Hey guys can you please help me with this math problem?

shusha [124]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

suppose Tomas buys a total of 30 baseball and football cards in week 5 . how many of each would he have to buy to keep the same

Charra [1.4K]

Answer:

18 baseball cards
12 football cards

Step-by-step explanation:

The only relationship shown in the table is in week 1, where the ratio of baseball to football cards is ...

baseball : football = 9 : 6

In week 1, the total of these numbers is 15. You want the total in week 5 to be 30, double the total in week 1. So, Thomas needs to purchase double the numbers he purchased in week 1:

18 baseball cards
12 football cards

_____

<em>Comment on the attachment</em>

This table came from another question you posted, a question with no content other than the table. The blue numbers are blanks in the original table that have been filled in so as to keep the same 3:2 proportion in each week. They appear to have no bearing on this question.

7 0

3 years ago

56% of what number is 84

vodomira [7]

84/56=1.5 - it is 1% of number
1.5*100=150
Answer: 150

4 0

3 years ago

What is the value of x in the equation?

mojhsa [17]

The answer is D, 1 3/5

6 0

2 years ago

A study of long-distance phone calls made from General Electric's corporate headquarters in Fairfield, Connecticut, revealed the

Jet001 [13]

Answer:

a) 0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

b) 0.0668 = 6.68% of the calls last more than 4.2 minutes

c) 0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

d) 0.9330 = 93.30% of the calls last between 3 and 5 minutes

e) They last at least 4.3 minutes

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 3.6, \sigma = 0.4$

(a) What fraction of the calls last between 3.6 and 4.2 minutes?

This is the pvalue of Z when X = 4.2 subtracted by the pvalue of Z when X = 3.6.

X = 4.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

X = 3.6

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.6 - 3.6}{0.4}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5

0.9332 - 0.5 = 0.4332

0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

(b) What fraction of the calls last more than 4.2 minutes?

This is 1 subtracted by the pvalue of Z when X = 4.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% of the calls last more than 4.2 minutes

(c) What fraction of the calls last between 4.2 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 4.2. So

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 3.6}{0.4}$

$Z = 3.5$

$Z = 3.5$ has a pvalue of 0.9998

X = 4.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.2 - 3.6}{0.4}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

0.9998 - 0.9332 = 0.0666

0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

(d) What fraction of the calls last between 3 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 3.

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 3.6}{0.4}$

$Z = 3.5$

$Z = 3.5$ has a pvalue of 0.9998

X = 3

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3 - 3.6}{0.4}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.9998 - 0.0668 = 0.9330

0.9330 = 93.30% of the calls last between 3 and 5 minutes

(e) As part of her report to the president, the director of communications would like to report the length of the longest (in duration) 4% of the calls. What is this time?

At least X minutes

X is the 100-4 = 96th percentile, which is found when Z has a pvalue of 0.96. So X when Z = 1.75.

$Z = \frac{X - \mu}{\sigma}$

$1.75 = \frac{X - 3.6}{0.4}$

$X - 3.6 = 0.4*1.75$

$X = 4.3$

They last at least 4.3 minutes

7 0

3 years ago