Answer : The number of bottles should the pharmacy technician prepare to provide the required dose are 4 bottles.
Step-by-step explanation :
As we are given that a patient needs a total dose of 50 grams of albumin and the pharmacy has 50 mL bottles of 25% Albumin in stock.
Now we have to determine the number of bottles should the pharmacy technician prepare to provide the required dose.
As,
The pharmacy has stock albumin = 
The pharmacy has stock albumin = 12.5 mL
So,
Number of bottles should the pharmacy technician prepare to provide the required dose = 
Number of bottles should the pharmacy technician prepare to provide the required dose = 4
Therefore, the number of bottles should the pharmacy technician prepare to provide the required dose are 4 bottles.
Answer:
How close the correlation is. the closer the correlation coefficient is to ±1, the stronger the correlation
Step-by-step explanation:
Hello, I hope this helped and that I was right, have a nice day.
Hi I couldn’t do the work for the surface area on the picture because I didn’t have space left so here it is,
Formula: 2(lw+lh+wh)
Shape 1
(2.4 x 1.1) + (2.4 x1.8) + (1.1 x 1.8)= 8.94
8.94 x 2= 17.88
Shape 2
(2.4 x 1.1) + (2.4 x 0.5) + (1.1 x 0.5) = 4.39
4.39 x2 = 8.78
17.88+ 8.78
<h3>
Answer: Approximately 35.54 degrees</h3>
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Explanation:
With respect to reference angle x, the 5 is the opposite side, and the adjacent side is 7 units long.
We'll use the tangent ratio here
tan(angle) = opposite/adjacent
tan(x) = 5/7
x = arctan(5/7)
x = 35.5376777919743 approximately
x = 35.54
I rounded to two decimal places, but you can round however you need to or however your teacher instructs. Arctangent is the same as inverse tangent. Be sure that your calculator is in degree mode.
The first time I did it, I got an answer that's not one of the choices. The second time
I did it, I got an answer that IS . Here are both of my procedures. If all you want is
the answer, look down below at the second one. But if you could help me out, now
that you know how to do this stuff, please look at my first solution and tell me where
I messed up. I can't find it.
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Here's what the problem tells you:
D = 10 log ( ' I ' / 10⁻¹² )
D = 60 . . . . . find ' I ' .
Here we go:
60 = 10 log ( ' I ' / 10⁻¹² )
Divide each side by 10 :
6 = log ( ' I ' / 10⁻¹² )
Raise 10 to the power of each side of the equation:
10⁶ = ' I ' / 10⁻¹²
Multiply each side by 10¹² :
10¹⁸ = ' I ' That's 10^18. It looks bad, because that isn't one of the choices.
Let's try a slightly different procedure:
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After substituting 10⁺¹² for I₀ , we're working with this formula:
D = 10 log ( 'I' / 10⁺¹² )
Let's just look at the log part of that.
The log of a fraction is [ log(numerator) - log(denominator) ]
log of this fraction is [ log( 'I' ) - log(10⁻¹²) ]
But log(10⁻¹²) is just (-12) .
So the log of the fraction is [ log( 'I' ) + 12 ]
And the whole formula is now:
D = 10 [ log( 'I' ) + 12 ]
60 = 10 [ log( 'I' ) + 12 ]
Divide each side by 10 :
6 = log( 'I' ) + 12
Subtract 12 from each side :
-6 = log ( ' I ' )
' I ' = 10⁻⁶
That's choice-'B' .
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I'm going to leave the first solution up there, in hopes that you, or one
of the many aces, experts, and geniuses that prowl this site constantly,
can weigh in and show me my blunder on the first attempt.
