Answer:
1931.7N
Step-by-step explanation:
We are told in the question that :
An auto ( a car) weighs = 2500 pounds
It s inclined at n horizontal Ange of 10°
We are asked to find the force that would prevents it from rolling down the street.
Since the unit for Force = Newton or kgm/s²
Step 1
Convert Weight in pounds to kg
1 pound = 0.453592kg
2500 pounds =
2500 pounds × 0.453592kg
= 1133.981kg
Step 2
Find the force that would prevents it from rolling down the street.
Force = Mass × Acceleration due to gravity × sin θ
Acceleration due to gravity = 9.81m/s
Force = 1133.981kg × 9.81 × sin 10°
Force = 1931.7237321 N
Approximately = 1931.7N
Answer:
ST = 20
Step-by-step explanation:
RT is the sum of RS and ST
Replacing with length you get:
17 + x + 6 = 3x - 56
17 + 6 + 5 = 3x - x
28 = 2x
14 = x
ST = x + 6 = 14 + 6 = 20
So it is 5cm to 1m or 5cm to 1000cm
So the scale is the ratio which is 5:1000. this can be reduced to 1:200
10. if the room is 15cm on one side I can say that the ratio to actual size is 15/x. and scale is 1/200 so:
15/x = 1/200
3000 = x is one side
other side:
20/x = 1/200
4000 = x
