Answer:
2.93cm
Step-by-step explanation:
I have to admit, this stumped me but I got o work and here's what I have for you. Hope this helps. TIP: remember it is the minute hand not any other hand.
For this one you will have to find the circumference of the clock because as the min hand goes round and round, it will act as a <u>radius</u> and it will go in a <u>circular</u> motion.
Formula will be π<u>2r</u>= 3.l4 * 2 * 1.4cm=8.792cm per every<u> one</u> revolution of the minute hand. Remembering that for the minute hand to revolve round the clock it has to cover 1 hr = 60min. For you to get the total circumference,
you'll have to take 8.792cm but since it is per every <u>one</u> revolution of the minute hand, multiply it by 40/60min. <u><em>The answer will be 2.93066cm </em></u><u><em>before rounding off</em></u>. After rounding off you will have <u>2.93cm</u>. Quite lengthy but I assure you after practicing you'll have at your fingertips.
Multiply all the numbers together to get the total amount of possible outcomes
20 x 13 x 35 = 9100
There are 9100 possible outcomes that Becky can get
hope this helps
Answer:
x = 2
Step-by-step explanation:
The product of distances from the intersection of secants to the near and far intersections with the circle are the same. For a tangent, the near and far points of intersection with the circle are the same. This relation tells us ...
(2√3)(2√3) = x(x +4)
12 = x² +4x
16 = x² +4x +4 . . . . . add the square of half the x-coefficient to complete the square
4² = (x +2)² . . . . . . . . write as squares
4 = x +2 . . . . . . . . . . positive square root
2 = x . . . . . . . . . . . . . subtract 2
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<em>Alternate solution</em>
If you believe x to be an integer, you can look for factors of 12 that differ by 4.
12 = 1×12 = 2×6 = 3×4
The factors 2 and 6 differ by 4, so x=2 and x+4=6.
5000 grams are equal to 5 kilograms
Domain includes all the x-values in the function. Range includes all the y-values in the function.
The first table has x-values of -1, 3, and 6, and y-values of 4, 5, and 6. This means that the domain and range would be given by the following sets:
Domain: {-1, 3, 6}
Range: {4, 5, 6}
The second set of points has x-values of -4, -4, -3, and 1, and y-values of 1, 1, 3, and 4. Duplicate points are not listed within the domain and range, so the domain and range would be given by the following sets:
Domain: {-4, -3, 1}
Range: {1, 3, 4}
