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ArbitrLikvidat [17]
3 years ago
9

1. Write (x^3)5 using a single exponent

3)^5 " alt="( x^3)^5 " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
BaLLatris [955]3 years ago
4 0

Answer:

X^15

Step-by-step explanation:

Since 3*5 is 15

So it becomes

X^15

xxMikexx [17]3 years ago
3 0

Answer:

x^15.

Step-by-step explanation:

(x^3)^5

= x^(3*5)

= x^15.

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MaRussiya [10]

Step-by-step explanation:

I believe this would be A or D

6 0
3 years ago
Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi
Oxana [17]

Answer:

Center: (-2, 4)

Radius: 4

Step-by-step explanation:

To find the centre and radius, we require to identify g , f and c

By comparing the coefficients of 'like terms' in the given equation with the general form.

2g = 4 → g = 2 , 2f = -8 → f = -4 and c = 4 → center=(−g,−f)=(−2,4)

radius = √22+(−4)2−4= √4+16−4=4

Center: (-2, 4)

Radius: 4

Hope This Helps! :)

8 0
3 years ago
Help!<br>Simplify:<br><br>2[45 ÷ (11 - 8) to the 2nd power] - 3​
GenaCL600 [577]

Answer:

The answer is 7

Step-by-step explanation:

Hope this helped :)

4 0
3 years ago
What is compare the values of the 2s and 5s in 55,220
Alina [70]

Compare Values of 2's   and   5's:

55,220

<u>5   ==>   Hundred-Thousands  Place</u>

<u>5   ==>      Ten-Thousands  Place</u>

<u>2   ==>      Thousands  Place</u>

<u>2    ==>    Hundreds  Place</u>

0   ======>          Tens  Place



Hope that helps!!!                                  : )

5 0
3 years ago
How many different 11-letter words (real or imaginary) can be formed from the letters in the word PROBABILITY?
Lostsunrise [7]
<h3>Answer:  9,979,200</h3>

This is one single number. It's just a bit under 10 million

Delete the commas if necessary.

==================================================

Explanation:

If we could tell the repeated letters apart, then there would be

11*10*9*8*7*6*5*4*3*2*1 = 39,916,800

different ways to scramble up the letters.

However, we have 2 copies of b and 2 copies of i

So we have to divide by 2*2 = 4 to correct this overcounting

(39,916,800)/4 = 9,979,200

6 0
3 years ago
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