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3 years ago

Evaluate b^2 for b= -4

Mathematics

2 answers:

fiasKO [112]3 years ago

6 0

Answer:

Step-by-step explanation:

We have the expression:

b^2

We know that b= -4. Therefore, we can substitute -4 in for b.

(-4)^2

-4^2 is the same as multiplying 4, 2 times.

-4^2

=-4*-4

2 negative numbers multiplied together make a positive number.

= 16

tekilochka [14]3 years ago

5 0

Answer:

Step-by-step explanation:

b^2

Let b= -4

(-4)^2

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3 years ago

Find the range of y = 3/2 cos 4x - 1

motikmotik

Answer:

B. $-2\frac{1}{2} \leq y \leq \frac{1}{2}$

Step-by-step explanation:

The given trigonometric function is

$f(x)=\frac{3}{2}cos4x-1$ .

The amplitude of this function is $\frac{3}{2}$ , so under normal circumstances the range is supposed to be

$-\frac{3}{2} \leq y \leq \frac{3}{2}$

But the $-1$ is a downward vertical shift.

Therefore the normal boundaries of the range will shift down one unit to give the range of the transformed function.

We subtract 1 from the lower boundary to get $-\frac{3}{2}-1=-2\frac{1}{2}$

We also subtract 1 from the upper boundary to get $-frac{3}{2}-1=\frac{1}{2}$

Hence the range is

$-2\frac{1}{2} \leq y \leq \frac{1}{2}$

Also see graph

5 0

3 years ago

I need help plz help me

sineoko [7]

Since the denominators are the same, just add the tops. 1x+2 all over y^2-8

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3 years ago