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Andrei [34K]
3 years ago
11

Simplify: 5 1/12 - 2 3/4 = Express your answer as a mixed number.

Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

Mixed Number Form: 2 1/3

Step-by-step explanation:

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The penny size d is given by the literal equation d = 4n - 2, solve for n
DedPeter [7]
Thanks for your question!

d = 4n -2
d + 2 = 4n
(d+2)/4 = n

Hope this helped!
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Pls help with iready question
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If the "some number" is represented by m, then "some number cubed" is m^3. The product of that and 2 is 2m^3. Eight more than that product is
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Solve by quadratic formula. x squared plus x plus 1 = 0
Tasya [4]

Remember that the quadratic formula is: \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}.


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In x^2 + x + 1 = 0, our a-value is 1, our b-value is also 1, and our c-value is also 1.


Thus, when we plug in our values into our formula, we get the answer:

\dfrac{-1 \pm \sqrt{1^2 - 4(1)(1)}}{2(1)} = \dfrac{-1 \pm \sqrt{-3}}{2}


Simplifying this answer using i = \sqrt{-1}, we get our final answer of:

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5 0
4 years ago
Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.
Assoli18 [71]

Answer:

±11.18

Step-by-step explanation:

the function is:

f(q)=q^2-125

and to find the roots we need to find which values of q makes the function result in zero:

q^2-125=0

solving for q:

q^2=125\\q=\sqrt{125}

A square root has two solutions, one positive and one negative, so the solutions are:

q=±\sqrt{125} ≈ ±11.18

the roots of the quadratic equation are +11.18 and -11.18

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How do you write the vertex form equation of the parabola #y=2x^2 +11x-6#?
liubo4ka [24]
The easist way to find the vertex is to complete the square:

y=2x^2 +11x-6  =>  <span>y=2[ x^2 + (11/2)x  + (11/2)^2   - (11/2)^2 ]  - 6  

This can be rewritten as 
                                y = 2[(x+11/2)^2 ] -(121/4) - 24/4

                                y = 2 (x+11/2)^2 - 145/4

this is the equation in vertex form.  The vertex is at (-11/2, -145/4).</span>
5 0
4 years ago
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