The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
<h3>How to find a sector area, and arc length?</h3>
For a sector that has a central angle of θ, and a radius of r;
The sector area, and the arc length are:
--- sector area
---- arc length
<h3>How to find the given sector area, and arc length?</h3>
Here, the given parameters are:
Central angle, θ = 160
Radius, r = 5 inches
The sector area is
So, we have:
Evaluate
A = 34.92
The arc length is:
So, we have:
L = 13.97
Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
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It takes 8 trees to make a stack 1.2 metres tall, so if ut takes 20 minutes per tree, then it will take 8 × 20 or 160 minutes, or 2 hours 40 minutes.
Step-by-step explanation:
Notice that
9y² - 4xy + 4x²/9 = (3y - 2x/3)².
Therefore (9y² - 4xy + 4x²/9) / (3y - 2x/3)
= (3y - 2x/3).
(4 x 7)1/2=
length times width and divided by two is how to find the area of a triangle
We'll first clear a few points.
1. A hyperbola with horizontal axis and centred on origin (i.e. foci are centred on the x-axis) has equation
x^2/a^2-y^2/b^2=1
(check: when y=0, x=+/- a, the vertices)
The corresponding hyperbola with vertical axis centred on origin has equation
y^2/a^2-x^2/b^2=1
(check: when x=0, y=+/- a, the vertices).
The co-vertex is the distance b in the above formula, such that
the distance of the foci from the origin, c satisfies c^2=a^2+b^2.
The rectangle with width a and height b has diagonals which are the asymptotes of the hyperbola.
We're given vertex = +/- 3, and covertex=+/- 5.
And since vertices are situated at (3,0), and (-3,0), they are along the x-axis.
So the equation must start with
x^2/3^2.
It will be good practice for you to sketch all four hyperbolas given in the choices to fully understand the basics of a hyperbola.
