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quester [9]
3 years ago
9

 A/An _______ is characteristic of children at age five. 

Biology
2 answers:
olya-2409 [2.1K]3 years ago
4 0
The answer is letter C
sashaice [31]3 years ago
3 0
Well its definitely not A lol. its C.
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How are red blood cells able to move through narrow vessels to carry oxygen throughout a multicellular organism? (1 point) a)The
geniusboy [140]

Answer:

The correct answer is - option B. They are small because they lack a nucleus.

Explanation:

Red blood cells or erythrocytes are specialized cell that produce in bone marrow and have specific role such as carrying oxygen from lungs to deliver it to the various organs and carry out carbon dioxide.

In mammals these cells lack cell organelles such as nucleus and mitochondria, a major factor that determined its smaller size. The size of RBC are move through narrow vessels throughout a organism because of its specific size and shape that provide it space for hemoglobin and allow to be flexible and bend to move through narrow vessels.

Thus, the correct answer is : option B. They are small because they lack a nucleus.

8 0
3 years ago
Which of the following is an example of primary waste prevention?
zmey [24]

The correct option is B, that is, A FAMILY DONATES USED CLOTHING TO A SECOND HAND STORE.

Waste prevention has to do with the process and practice of reducing the amount of wastes products in order to produce a more sustainable environment. Waste prevention can also be called recycling. There are three types of waste prevention, these are primary, secondary and tertiary waste prevention / recycling.

Primary waste prevention refers to a situation in which the material to be disposed is not changed in anyway, before been reused. Such material can be given to friend or donated to a charity organization. The material is always used for the same purpose as the original use.  

Secondary waste prevention involves some kind of modifications while tertiary waste prevention usually involves the use of chemicals and heat.  

4 0
3 years ago
Read 2 more answers
Which of the following terms refers to a person's ability to reason speedily and abstractly?
mina [271]

Answer:

d. Fluid intelligence

Explanation:

Fluid intelligence -

It is the capacity to solve the problem in a novel situations and think logically and independence regarding the acquired knowledge .

The ability of fluid intelligence involves to determine the patterns and relationships which holds the novel problems and to assume these findings using logic .

Hence , the correct option for the given information is d. Fluid intelligence .

5 0
3 years ago
PLEASE HELP ME CORRECT ANSWERS ONLY
marysya [2.9K]

Answer:

Choice one: Met, Phe, Leu, Pro, Lys, Stop

Explanation:

It does not want you to find the pairs of the mRNA, just find what protein each part of that strand hooks up to. Follow the flow of the chart, and you get your proteins.

8 0
2 years ago
Read 2 more answers
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is
IgorC [24]

Answer:

When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0

Explanation:

According to Levin's model (1969):

<em>dP/dt = c - e</em>

where P represents the proportion of occupied patches.

<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.

Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:

  • if dP/dt >0, then P is increasing with time
  • if dP/dt <0, then P is decreasing with time
  • if dP/dt = 0, then P is remaining the same with time.

The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).

c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0  and  1.

As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.

7 0
3 years ago
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