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tatiyna
3 years ago
15

When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is

Biology
1 answer:
IgorC [24]3 years ago
7 0

Answer:

When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0

Explanation:

According to Levin's model (1969):

<em>dP/dt = c - e</em>

where P represents the proportion of occupied patches.

<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.

Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:

  • if dP/dt >0, then P is increasing with time
  • if dP/dt <0, then P is decreasing with time
  • if dP/dt = 0, then P is remaining the same with time.

The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).

c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0  and  1.

As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.

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