Can someone help me please

Totsaken sold half of his comic books and bought ten more. He now has 40. With how many did he begin?

AURORKA [14]

The answer is 60 because

40-10*2=60

hope it helps

8 0

3 years ago

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Which of the accounts below are considered accrued expenses?

umka21 [38]

Answer:

Accrued expenses are those liabilities that have built up over time and are due to be paid. Accrued expenses are considered to be current liabilities because the payment is usually due within one year of the date of the transaction. Accounts payable are current liabilities that will be paid in the near future.

8 0

3 years ago

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Do you know how to do this question

Sever21 [200]

Percentage of the area shaded = 55%

Solution:

Perimeter of the square = 40 cm

Each side of the square = $\frac{40}{4}$ = 10 cm

Area of the square = $\text{side}^2$

= 10²

= 100

Total area of the square = 100 cm²

The unshaded portion is two triangles.

Base of the smaller triangle = 10 cm – 7 cm = 3 cm

Height of the smaller triangle = 10 cm

Area of the smaller triangle = $\frac{1}{2}\times \text{base}\times \text{height}$

$$=\frac{1}{2}\times 3\times 10$

Area of the smaller triangle = 15 cm²

Base of the larger triangle = 10 cm – 4 cm = 6 cm

Height of the larger triangle = 10 cm

Area of the larger triangle = $\frac{1}{2}\times \text{base}\times \text{height}$

$$=\frac{1}{2}\times 6\times 10$

Area of the larger triangle = 30 cm²

Area of the shaded portion = Area of the square – Area of the smaller

triangle – Area of the larger triangle

= 100 cm² – 15 cm² – 30 cm²

Area of the shaded portion = 55 cm²

Percentage of the area shaded = $\frac{\text{Area of the shaded portion}}{\text{Total area of the square}}\times100\%$

$$=\frac{55}{100}\times100\%$

Percentage of the area shaded = 55%

8 0

4 years ago

What is a short method to show the compound inequality x < 2 AND x > 7

jeyben [28]

These inequalities are not compatible: you are looking for a number that is less than 2, but more than 7. This is impossible, because if a number is less than 2, it can't be more than 7.

Conversely, if a number is more than 7, it can't be less than 2.

8 0

4 years ago

Consider Functions F and G

Zanzabum

Answer:

A

Step-by-step explanation:

We are given two functions:

$\displaystyle f(x)=\frac{x-16}{x^2+6x-40}\text{ and } g(x)=\frac{1}{x+10}$