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GarryVolchara [31]
3 years ago
11

Rick has 1/2 of a footlong sub left from yesterday. He ate 1/3 of the leftover sandwich as a snack. What fraction of the entire

sandwich did he eat
as a snack? ​
Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:2/6

Step-by-step explanation: because 1+1=2 and then  you find the lcm of 2and3 then u get your aanswer

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Willa says the slope of the graph is - 3. What error did
Yuri [45]

Answer:B

Step-by-step explanation: “she counted the squares instead of using the scale” by looking at the graph the first coordinates are (4,24) and instead of doing that Willa counted the squares.

5 0
3 years ago
Pedro has twice as many carrots as Martha, who has the same number of carrots as Oliver. If Pedro gives 5 carrots to Oliver, the
choli [55]
"Pedro has twice as many carrots as Martha:"
p = 2m
<span>
"If Pedro gives 5 carrots to Oliver," 
p - 5  (</span>Oliver is irrelevant.)<span>

"then Martha has 3 times as many carrots as Pedro"
</span>
m = 3(p - 5)

We know p in terms of m, so substitute it in:
m = 3(2m - 5)

Distribute the 3:
m = 6m - 15

Subtract 6m from both sides:
m-6m=-15
Combine variable terms:

-5m=-15

Divide out -5

m = -15/-5

m = 3

The answer is c) 3  







3 0
3 years ago
North safety products manufactures butyl gloves that offer permeation resistance to gas or water vapors for workers that use dan
never [62]

Company fixed cost = $10 million = $10,000,000

Variable cost per pair = $5

Company charges each pair = $15

Hence the company makes $10 profit per pair regardless the company fixed cost and only considering the variable cost.

Let subtract the variable cost per pair from the company charging each pair = 15 - 5 = $10

Thus the company now makes $10 per pair, and it has to sell 1,000,000 pairs of gloves to reach the break-even point. The break-even point refers to the point where total cost and revenue are equal.

<span>Thus for 1,000,000 pairs, the company total earning = 10 x 1,000,000 = $10,000,000 = $10 million  </span>

4 0
3 years ago
What is the five number summary for the data set 0,2,2,4,5,5,5,5,7,11
dimaraw [331]

Answer:

The median/middle is 5 and the minimum is 0 and the maximum is 11. The first quartile is 7/5= 1.4 and the second is 4/2 = 2

Step-by-step explanation:

7 0
2 years ago
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Anuta_ua [19.1K]

Answer:

c

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right] ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]

After that, to reach the desired second column, we can divide the second row by 14, resulting in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0
3 years ago
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