Ths phrase that represents the algebraic expression (3p + 6)/(7p - 9) will be D. the sum of three times a number and six divided by the difference of seven times the number and nine.
<h3>How to illustrate the algebra?</h3>
It should be noted that an algebra is simply used to show the relationship between variables.
Here, the phrase that represents the algebraic expression (3p + 6)/(7p - 9) will be the sum of three times a number and six divided by the difference of seven times the number and nine.
In conclusion, the correct option is D.
Learn more about algebra on:
brainly.com/question/723406
#SPJ1
To complete the square:
we take the coefficient ox "x" (which in this problem is -20)
we divide it by 2
square that number
then add it to both sides of the equation
-20 / 2 = -10
-10^2 = 100
then we add 100 to both sides of the equation:
x^2 -20x
x^2 -20x +100 = 100
******************************************************
To get the roots of the equation, we take the square root of both sides:
(x -10) * (x-10) = 10
(x-10) = square root (10)
x-10 =
<span>
<span>
<span>
3.1622776602
</span>
</span>
</span>
x1 =
<span>
<span>
<span>
13.1622776602
</span>
and don't forget that square root of 10 also equals </span></span><span><span><span> -3.1622776602
</span>
</span>
</span>
x2 = 10
-<span>
<span>
<span>
3.1622776602
x2 = </span></span></span>
<span>
<span>
<span>
6.8377223398
</span>
</span>
</span>
9=m-4
9+4=m
13=m
9=13-4
9=9
I hope this answer helped you!!! Thank you!!!
Answer:
no solutions
Step-by-step explanation:
6n - 6n - 12 = 14 - 2 = 12 ( add 12 to both sides )
0 = 24 ← not possible
this indicates the equation has no solution
Answer:
5mph
Step-by-step explanation:
Given that two cars are 40 miles apart at the beginning.
They started at the same time with speeds 48 mph and 56 mph respectively
Since both cars are travelling in the same direction,
Relative velocity = Speed of the behind car-Speed of the first car
=56-48 =8mph
To catch the I car, the second car has to travel a distance of 40 miles extra in the same time as the I car
i.e. speed to be made up by the second car = 40 miles
Relative velocity per hour = 8mph
Hence time taken to catch up = 
