(y-4)(y^2+4y+16)
y^3+4y^2+16y-4y^2-16y-64=y^3+4y^2+ay-4y^2-ay-64
Comparing the coefficients: a=16
Answer: The value of a in the polynomial is 16
-5x + y = -5.....multiply by -2
-4x + 2y = 2
---------------
10x - 2y = 10 (result of multiplying by -2)
-4x + 2y = 2
-----------------add
6x = 12
x = 12/6
x = 2
-5x + y = -5
-5(2) + y = -5
-10 + y = -5
y = -5 + 10
y = 5
solution is (2,5)
Answer:
akhavkreugvakrehfgv
Step-by-step explanation:
Answer:
2006
Step-by-step explanation:
1 + 2(1027) + 6 + 7 - 8 • 9 + 10
1 + 2054 + 6 + 7 - 72 + 10
2006
