Question

How can I solve y^2 + 13y + 12?

Answer 1

(y+1)(y+12) that’s what I got.

Answer 2

$(y + 1)(y + 12)$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

${y}^{2} + 13y + 12 \\ = {y}^{2} + 12y + 1y + 12 \\ taking \: common \: factor \: from \: the \: two \: pairs \\ = y(y + 12) + 1(y + 12) \\ = (y + 1)(y + 12)$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}$