How can I solve y^2 + 13y + 12?

Mathematics

2 answers:

zavuch27 [327]2 years ago

8 0

(y+1)(y+12) that’s what I got.

lidiya [134]2 years ago

7 0

$(y + 1)(y + 12)$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

${y}^{2} + 13y + 12 \\ = {y}^{2} + 12y + 1y + 12 \\ taking \: common \: factor \: from \: the \: two \: pairs \\ = y(y + 12) + 1(y + 12) \\ = (y + 1)(y + 12)$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}$

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A. 12 + 4x = 6x + 10 – 2x

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A) $12+4x=6x+10-2x \iff 12+4x=10+4x \iff 12=10$