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AleksandrR [38]
3 years ago
11

How can I solve y^2 + 13y + 12?

Mathematics
2 answers:
zavuch27 [327]3 years ago
8 0
(y+1)(y+12) that’s what I got.
lidiya [134]3 years ago
7 0

(y + 1)(y + 12)

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

{y}^{2}  + 13y + 12 \\  =  {y}^{2}  + 12y + 1y + 12 \\  taking \: common \: factor \: from \: the \: two \: pairs \\ = y(y + 12) + 1(y + 12) \\  = (y + 1)(y + 12)

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}

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