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3 years ago

How can I solve y^2 + 13y + 12?

Mathematics

2 answers:

zavuch27 [327]3 years ago

8 0

(y+1)(y+12) that’s what I got.

lidiya [134]3 years ago

7 0

$(y + 1)(y + 12)$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

${y}^{2} + 13y + 12 \\ = {y}^{2} + 12y + 1y + 12 \\ taking \: common \: factor \: from \: the \: two \: pairs \\ = y(y + 12) + 1(y + 12) \\ = (y + 1)(y + 12)$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}$

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h(x) = -16x² + 192x + 208

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Step-by-step explanation:

h(x) = -16x² +vx + h $_{o}$

here v represent velocity

$h_{o}$ represent initial height of launch

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Factors

1x * -13x = -13

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Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

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<h3>What is Average Rate?</h3>

A single rate that is a weighted average of the different rates that are applicable to property in various locations.
An average is a single number calculated as the average of a set of numbers, typically calculated as the sum of the numbers divided by the total number of numbers in the set (the arithmetic mean).

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The difference of years between the year 2006 and 1992 = 2006 - 1992 = 14

average rate of change of credit card debt with respect to time = $\frac{difference of credit card debt}{difference of years}$

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know more about average numerical brainly.com/question/18296887

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