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3 years ago

7

This is a picture of a cube and the net for the cube.

2 answers:

Art [367]3 years ago

7 0

Hey that answer is 54 in^2

Mnenie [13.5K]3 years ago

4 0

Hello the answer would be 54 in^2 hope this help you and have a very nice day!

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What is the equation in point slope form for a linear function with a slope of m = -4 that passes through the

Alex_Xolod [135]

Y + 7 = -4(x - 2)

The equation for point slope form is
y - y1 = m(x - x1) where m represents the slope.

It coordinates and slope are given, they just need to be plugged into the equation.

y - (-7) = -4(x - 2)

Subtracting a negative can be written as adding a positive, so the equation can be simplified as:

y + 7 = -4(x - 2)

4 0

3 years ago

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng

gladu [14]

${\bold{\red{\huge{\mathbb{QUESTION}}}}}$

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

$\bold{ \red{\star{\blue{GIVEN }}}}$

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

$\bold{\blue{\star{\red{TO \: \: FIND}}}}$

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

$\bold{ \green{ \star{ \orange{FORMULA \: USED}}}}$

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

$AREA = ANGLE \: \: IN \: \: RADIAN \times RADIUS$

$\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}$

Total Area Of The Semi Sphere:-

$AREA = \pi \times radius \\ \\ AREA = \pi \times 2 = 2\pi$

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

$AREA = \frac{\pi}{3} \times radius \\ \\ AREA = \frac{\pi}{3} \times 2 \\ \\ AREA = \frac{2\pi}{3}$

$\green{Now:- } \\ \green{ \: Area \: Under \: Unshaded \: Part }$

Total Area - Area Under Unshaded Part

$Area= 2\pi - \frac{2\pi}{3} \\ Area = \frac{6\pi - 2\pi}{3} \\ Area = \frac{4\pi}{3} \: \: ans$

$\red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star$

5 0

3 years ago

An isoceles triangle has two long sides and one short side. The short side is half the length of a long side. If the perimeter o

devlian [24]

Answer:

3cm

Step-by-step explanation:

so the long sides are 6cm and the short sides are 3cm

4 0

3 years ago

HOW DO IT???<br> A<br> B<br> C<br> D

OLga [1]

B cuz x is five and 6.5 is 30

5 0

3 years ago

17+p=7p-13 Plz help me asap

Hunter-Best [27]

First you had to subtract by seventeen from both sides of equation form.

$17+p-17=7p-13-17$

Then simplify.

$p=7p-30$

Next, subtract by seven-p from both sides of equation form.

$p-7p=7p-30-7p$

Simplify.

$-6p=-30$

Then you divide by negative six from both sides of equation form.

$\frac{-6p}{-6}= \frac{-30}{-6}$

And finally, simplify by equation.

$-30/-6=5$

Final answer: $\boxed{p=5}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

4 0

3 years ago