Recall that to calculate the distance between two points (a,b) and (c,d) we use the formula
![\sqrt[]{(c-a)^2+(d-b)^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%28c-a%29%5E2%2B%28d-b%29%5E2%7D)
In our case we have a=-2, b=5, c=4 and d=5. So we get
![\sqrt[]{(4-(-2))^2+(5-5)^2}=\sqrt[]{6^2}=6](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%284-%28-2%29%29%5E2%2B%285-5%29%5E2%7D%3D%5Csqrt%5B%5D%7B6%5E2%7D%3D6)
So the distance between both points is 6
Answer E
Step-by-step explanation:
use Caculator very easy please dont ask
It seems a lot like 120. 60 and 60 rounded is 60 each. 60 + 60 = 120
(sorry if i'm wrong)
Minus 1 both sides
x²-8x=-1
take 1/2 of the linear coefient and square it
-8 is the linear coefient
-8/2=-4, (-4)²=16
add 16 to both sides
x²-8x+16=16-1
factor perfect squaer trinomial
(x-4)²=15
square root both sides, remember to take positive and negative roots
x-4=+/-√15
not exactly sure what to put in the blnaks
but
the solutions are x=4+√15 and x=4-√15
-1(18+4x)=8
Then you distribute
-18-4x=8
-4x=26
X= -6.5
