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coldgirl [10]
3 years ago
14

Will somebody please answer this question? I'm stuck and in a bit of a hurry. A surfboard shaper has to limit the cost of develo

pment and production to ​$ 215 per surfboard. He has already spent ​$ 30,240 on equipment for the boards. The development and production costs are ​$ 143 per board. The cost per board is 143x+30,240/x dollars. Determine the number of boards that must be sold to limit the final cost per board to $ 215.
Mathematics
1 answer:
ikadub [295]3 years ago
8 0

Answer:

  ≥ 420 boards

Step-by-step explanation:

Write the required relation between cost per board and "x" (the number of boards that must be sold).

  143 + 30240/x ≤ 215 . . . . . . . note that the first term is <em>not</em> 143x

Subtract 143

  30240/x ≤ 72

Multiply by x/72. This is a positive number because x is a positive number.

  30240/72 ≤ x

  420 ≤ x

At least 420 surfboards must be sold to limit the final cost per board to $215.

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