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BARSIC [14]
2 years ago
9

Write the equation in y=mx+b form please????

Mathematics
1 answer:
Solnce55 [7]2 years ago
6 0

ANSWER

y =  - 2x - 5

EXPLANATION

We can use any two points to determine the slope.

The line passes through;

(-3,1) and (-5,5).

The slope is given by

m =  \frac{y_2-y_1}{x_2-x_1}

This implies that;

m =  \frac{5 - 1}{ - 5 -  - 3}

m =  \frac{4}{ - 2}  =  - 2

We can now find the equation using the formula;

y-y_1=m(x-x_1)

y   - 1 =  - 2(x  + 3)

Expand:

y =  - 2x -6 + 1

y =  - 2x - 5

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Answer:

Part 1. 50 and 17 denotes that he earns $50 for each shift he works at the dinner and $17 for each dog-walking job.

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Part 2. The income from shift of work at the diner that is 50x, and the income from dog walking work that is 17y.

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Each week, Aubrey earns $50 for every shift he works at the diner and $17 for every dog-walking job.  

He uses the expression (50x + 17y) to keep track of his earning.

Part 1. Here the coefficient of the expressions 50 and 17 denotes that he earns $50 for each shift he works at the dinner and $17 for each dog-walking job.

And the variable x denotes the number of shifts at the dinner and y variable denotes the number of dog -walking jobs.

Part 2. Therefore, there are two terms in the expression, one is the income from the shift of work at the diner that is 50x and the other is the income from dog walking work that is 17y.

Part 3. The total income from the diner is given by 50x. (Answer)

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A diver jumps up and over from a cliff in order to avoid rocks and land in the deeper water. The path of the dive can be modeled
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Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

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