Which equation is a direct variation function?<br> O y=x<br> O y = x + 2<br> O y=&<br> Oy=4

Mr. Clark claims that he has a coin that is weighted so that the probability of heads is 40%. To test this, his students flip th

Brrunno [24]

While I'm unsure what the word choices were, his claim is likely to be true.

Since he claims the probability of heads is 40%, that should be what we see in an experiment. 0.38 is very close to 0.40, or 40%, so this is true. Therefore his claim is likely to be true, and the probability of tails should be about 60%.

5 0

2 years ago

Cuál es el denominador común de las fracciones?

Andreyy89

Answer:

?????????????????????????

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th

alexira [117]

Answer:

The inner function is $h(x)=4x^2 + 8$ and the outer function is $g(x)=3x^5$ .

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

Step-by-step explanation:

A composite function can be written as $g(h(x))$ , where $h$ and $g$ are basic functions.

For the function $f(x)=3(4x^2+8)^5$ .

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have $4x^2+8$ inside parentheses. So $h(x)=4x^2 + 8$ is the inner function and the outer function is $g(x)=3x^5$ .

The chain rule says:

$\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)$

It tells us how to differentiate composite functions.

The function $f(x)=3(4x^2+8)^5$ is the composition, $g(h(x))$ , of

outside function: $g(x)=3x^5$

inside function: $h(x)=4x^2 + 8$

The derivative of this is computed as

$\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4$

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

3 0

3 years ago

Male tigers weigh about 500 pounds. Female tigers weigh about 300

erica [24]

Answer:A

Step-by-step explanation:

4 0

2 years ago

Text wants to make a lawn in front of his house. He buys enough sod to make a 10 ft.by 30 ft. rectangle section of sod for $200

Trava [24]

This isn't a question. What is the question?

3 0

3 years ago

Which equation is a direct variation function? O y=x O y = x + 2 O y=& Oy=4