Given data:
The first equation is 3j +14=-5z.
The second equation is -10j=5z .
Add both the equations.
![\begin{gathered} (3j+14)+(-10j)=-5z+5z \\ -7j+14=0 \\ 7j=14 \\ j=2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%283j%2B14%29%2B%28-10j%29%3D-5z%2B5z%20%5C%5C%20-7j%2B14%3D0%20%5C%5C%207j%3D14%20%5C%5C%20j%3D2%20%5Cend%7Bgathered%7D)
Substitute 2 for j in the first equation.
![\begin{gathered} 3(2)+14=-5z \\ 20=-5z \\ z=-4 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%203%282%29%2B14%3D-5z%20%5C%5C%2020%3D-5z%20%5C%5C%20z%3D-4%20%5Cend%7Bgathered%7D)
Thus, the value of j is 2 and z is -4.
Answer:
47/10 - 3.2
Step-by-step explanation:
Given
Dolphin = 3.2
Bird = 47/10
Required
What is the vertical distance between both
Using a vertical scale;
Represent the bird "above sea level" position with positive and dolphin at "below sea level" position with negative.
The vertical distance between them is as follows;
Distance = +[Above The Sea] - [Below The Sea]
Distance = +47/10 - 3.2
Distance = 47/10 - 3.2
Hence, the vertical distance between both is 47/10 - 3.2
The answer is: b - lies in quadrant II when graphed.
Explanation:
Any number less than zero is a negative number.
Example: -1
Any number greater than zero is a positive number.
Example: 1
(a, f(a))
(-1,1)
When these example points are graphed, they are placed in the second quadrant.
Answer:
0.5
Step-by-step explanation:
1/2 is one half, and if you divide 1 by 2 using long division you get 0.5