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faltersainse [42]

3 years ago

8

What is equal to 4/5

2 answers:

nikitadnepr [17]3 years ago

7 0

8/10 is equal to 4/5.

Vika [28.1K]3 years ago

6 0

95% 95% 95% 95% 95% 95%

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50 points! Will mark the brainliest! What are the coordinates of the vertex of the graph of f(x)=2|x−3|?

Rom4ik [11]

Answer: (1,-2) (0,-3)

Step-by-step explanation:

brainliest plz

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Figure 1<br> 4n + 5<br> 6n<br> 4n - 5<br> 4n

Lunna [17]

Answer:

4n+5= 6n

4n-5 = 4n

Step-by-step explanation:

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During Halloween Billy Bob gave out 150 pieces of candy. Sally Belle gave out 200 pieces of candy. What is the ratio of candy Bi

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Express (sin 67° + cos 75°) in terms of trigonometric ratios of the angle

Furkat [3]

Answer:

cos23 + sin15

Step-by-step explanation:

sinQ = cos(90-Q)

cosQ = sin(90-Q)

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= cos23 + sin15

please mark me as brainliest

4 0

3 years ago

Given: ΔАВС, m∠ACB = 90° CD ⊥ AB , m∠ACD = 30°,AD = 8 cm Find: Perimeter of ΔABC

Iteru [2.4K]

Answer:

Perimeter of $\triangle ABC$ is $48+16\sqrt{3}$ .

Explanation:

Given: In $\triangle ABC$ , $\angle ACB = 90^{\circ}$ , $\angle ACD= 30^{\circ}$ and AD= 8cm.

In $\triangle ADC$

Sum of the measure of the angles of triangles is 180 degree.

$\angle CAD+\angle CDA+\angle ACD=180^{\circ}$

$\angle CAD+90^{\circ}+30^{\circ}=180^{\circ}$ or

$\angle CAD+120^{\circ}=180^{\circ}$

Simplify:

$\angle CAD=60^{\circ}$

∵ AD= 8cm and $\angleACD= 30^{\circ}$ to calculate the length of CD we use tangent ratio i.e,

$\tan = \frac{perpendicular}{Adjacent}$

then;

$\tan 30 = \frac{8}{CD}$ or

$\frac{1}{\sqrt{3}} =\frac{8}{CD}$

Simplify:

$CD=8\sqrt{3}$ cm.

Also, find the length of AC, we use sine ratio i.e, $\sin=\frac{perpendicular}{Hypotenuse}$ .

Then,

$\sin 30 =\frac{AD}{AC}$ or

$\frac{1}{2} =\frac{8}{AC}$

On simplify:

$AC=2\times 8 =16$ cm.

Now, in triangle ABC;

$\angle BAC= 60^{\circ}$ , $\angle ACB= 90^{\circ}$ then

$\angle ABC= 30^{\circ}$ [Sum of the measure of the angles in the triangle is 180 degree]

To calculate the length of BC;

$\tan A = \frac{BC}{AC}$ [∴ $\ tan= \frac{perpendicular}{adjacent}$ ]

therefore,

$\tan 60 = \frac{BC}{16}$

or

$\sqrt{3}= \frac{BC}{16}$

Simplify:

$BC=16\sqrt{3}$ cm.

Using Pythagoras theorem in triangle ACB;

Let BD be x cm

AB = 8+x cm , AC = 16 cm and $BC=16\sqrt{3}$ cm

$AB^2=AC^2+BC^2$

$(8+x)^2=(16)^2+(16\sqrt{3} )^2$ or

$(8+x)^2=256+768=1024$ or

$8+x=\sqrt{1024} =32$

Simplify:

x=24 cm

Therefore, the length of AB = 8+x= 8+24=32 cm

Perimeter(P) of triangle ABC is equal to the sum of the sides of the triangle.

⇒ P= AB+BC+AC = $32+16\sqrt{3} +16=48+16\sqrt{3}$ cm

4 0

3 years ago