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OleMash [197]
4 years ago
8

Which statement is true for the equation 4x − 4x − 5 = −5?

Mathematics
2 answers:
velikii [3]4 years ago
7 0
4x-4x-5=-5  combine like terms on left side

-5=-5

The above is true for all values of x, thus there are infinitely many solutions.
alisha [4.7K]4 years ago
5 0
4x - 4x -5 = -5
0 - 5 = -5
0 = 0
The equation has infinitely many solutions.
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And I'm stuck again ahahah.
IceJOKER [234]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Angle XBC = 55 degrees because corresponding angles are equal

b) We already know angle XBC

Angle XCB = Angle XBC because isosceles base angles are equal

Therefore, angle XCB = 55 degrees

Angles in a triangle equal 180 degrees

180 - (55 + 55) = 70

Angle BXC = 70 degrees

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

6 0
3 years ago
Read 2 more answers
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
Graph the system of equations.
Y_Kistochka [10]

Answer:

Step-by-step explanation:

I cannot use the line tool for you, but I can rewrite the equations

y = -x + 4 is good enough

Two points for this graph:

x = 0 -> y = 4 gives the point (0, 4)

x = 1 -> y = 3 gives the point (1, 3)

18x + 6y = -6

6y = -18x - 6

y = -3x - 2

Two ponts for this graph:

x = 0 -> y = -2 gives the point (0, -2)

x = 1 -> y = -5 gives the point (1, -5 )

4 0
3 years ago
Find the measures of the acute angles of the right triangle shown
yanalaym [24]

9514 1404 393

Answer:

  • 2x° = 64°
  • (x-6)° = 26°

Step-by-step explanation:

The acute angles in a right triangle are complementary:

  2x° +(x -6)° = 90°

  3x = 96 . . . . . . . . . divide by °, add 6

  x = 32 . . . . . . . . . divide by 3

  (x-6)° = (32 -6)° = 26°

  2x° = 2(32)° = 64°

The acute angles have measures 26° and 64°.

7 0
3 years ago
1/7 rounded to 2 decimal places
dmitriy555 [2]

Answer:

0.14

Step-by-step explanation:

1/7 = 0.142

Since 2<5 the answer is 0.14.

5 0
3 years ago
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