we have the number
![6-\sqrt[]{-40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B-40%7D)
Remember that
i^2=-1
so
substitute
![6-\sqrt[]{(i^2)40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B%28i%5E2%2940%7D)
![6-2i\sqrt[]{10}](https://tex.z-dn.net/?f=6-2i%5Csqrt%5B%5D%7B10%7D)
therefore
the real part is 6
the imaginary part is -2√10
Answer:
9
Step-by-step explanation:
Fun fact. The name nonagon comes from Greek enneagonon, and is arguably more correct, though less common than "nonagon".
Answer:
Step-by-step explanation:
You pretty much just flip the second fraction and factor
3 quarts, because 12 is how many cups you have, and there are 4 cups in a quart. 12/4 is 3, so 3 quarts.